{ "data": { "question": { "questionId": "944", "questionFrontendId": "908", "categoryTitle": "Algorithms", "boundTopicId": 1346, "title": "Smallest Range I", "titleSlug": "smallest-range-i", "content": "

You are given an integer array nums and an integer k.

\n\n

In one operation, you can choose any index i where 0 <= i < nums.length and change nums[i] to nums[i] + x where x is an integer from the range [-k, k]. You can apply this operation at most once for each index i.

\n\n

The score of nums is the difference between the maximum and minimum elements in nums.

\n\n

Return the minimum score of nums after applying the mentioned operation at most once for each index in it.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [1], k = 0\nOutput: 0\nExplanation: The score is max(nums) - min(nums) = 1 - 1 = 0.\n
\n\n

Example 2:

\n\n
\nInput: nums = [0,10], k = 2\nOutput: 6\nExplanation: Change nums to be [2, 8]. The score is max(nums) - min(nums) = 8 - 2 = 6.\n
\n\n

Example 3:

\n\n
\nInput: nums = [1,3,6], k = 3\nOutput: 0\nExplanation: Change nums to be [4, 4, 4]. The score is max(nums) - min(nums) = 4 - 4 = 0.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "最小差值 I", "translatedContent": "

给你一个整数数组 nums，和一个整数 k 。

\n\n

在一个操作中，您可以选择 0 <= i < nums 的任何索引 i 。将 nums[i] 改为 nums[i] + x ，其中 x 是一个范围为 [-k, k] 的整数。对于每个索引 i ，最多 只能 应用 一次 此操作。

\n\n

nums 的 分数 是 nums 中最大和最小元素的差值。 

\n\n

在对nums中的每个索引最多应用一次上述操作后，返回 nums 的最低 分数 。

\n\n

 

\n\n

示例 1：

\n\n
\n输入：nums = [1], k = 0\n输出：0\n解释：分数是 max(nums) - min(nums) = 1 - 1 = 0。\n
\n\n

示例 2：

\n\n
\n输入：nums = [0,10], k = 2\n输出：6\n解释：将 nums 改为 [2,8]。分数是 max(nums) - min(nums) = 8 - 2 = 6。\n
\n\n

示例 3：

\n\n
\n输入：nums = [1,3,6], k = 3\n输出：0\n解释：将 nums 改为 [4,4,4]。分数是 max(nums) - min(nums) = 4 - 4 = 0。\n
\n\n

 

\n\n

提示：

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