<p>Design a special dictionary with some words that searchs the words in it by a prefix and a suffix.</p> <p>Implement the <code>WordFilter</code> class:</p> <ul> <li><code>WordFilter(string[] words)</code> Initializes the object with the <code>words</code> in the dictionary.</li> <li><code>f(string prefix, string suffix)</code> Returns <em>the index of the word in the dictionary,</em> which has the prefix <code>prefix</code> and the suffix <code>suffix</code>. If there is more than one valid index, return <strong>the largest</strong> of them. If there is no such word in the dictionary, return <code>-1</code>.</li> </ul> <p> </p> <p><strong>Example 1:</strong></p> <pre> <strong>Input</strong> ["WordFilter", "f"] [[["apple"]], ["a", "e"]] <strong>Output</strong> [null, 0] <strong>Explanation</strong> WordFilter wordFilter = new WordFilter(["apple"]); wordFilter.f("a", "e"); // return 0, because the word at index 0 has prefix = "a" and suffix = 'e". </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= words.length <= 15000</code></li> <li><code>1 <= words[i].length <= 10</code></li> <li><code>1 <= prefix.length, suffix.length <= 10</code></li> <li><code>words[i]</code>, <code>prefix</code> and <code>suffix</code> consist of lower-case English letters only.</li> <li>At most <code>15000</code> calls will be made to the function <code>f</code>.</li> </ul>