{ "data": { "question": { "questionId": "3018", "questionFrontendId": "2825", "boundTopicId": null, "title": "Make String a Subsequence Using Cyclic Increments", "titleSlug": "make-string-a-subsequence-using-cyclic-increments", "content": "

You are given two 0-indexed strings str1 and str2.

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In an operation, you select a set of indices in str1, and for each index i in the set, increment str1[i] to the next character cyclically. That is 'a' becomes 'b', 'b' becomes 'c', and so on, and 'z' becomes 'a'.

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Return true if it is possible to make str2 a subsequence of str1 by performing the operation at most once, and false otherwise.

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Note: A subsequence of a string is a new string that is formed from the original string by deleting some (possibly none) of the characters without disturbing the relative positions of the remaining characters.

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Example 1:

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\nInput: str1 = "abc", str2 = "ad"\nOutput: true\nExplanation: Select index 2 in str1.\nIncrement str1[2] to become 'd'. \nHence, str1 becomes "abd" and str2 is now a subsequence. Therefore, true is returned.
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Example 2:

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\nInput: str1 = "zc", str2 = "ad"\nOutput: true\nExplanation: Select indices 0 and 1 in str1. \nIncrement str1[0] to become 'a'. \nIncrement str1[1] to become 'd'. \nHence, str1 becomes "ad" and str2 is now a subsequence. Therefore, true is returned.
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Example 3:

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\nInput: str1 = "ab", str2 = "d"\nOutput: false\nExplanation: In this example, it can be shown that it is impossible to make str2 a subsequence of str1 using the operation at most once. \nTherefore, false is returned.
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Constraints:

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Consider the indices we will increment separately.
", "
We can maintain two pointers: pointer i for str1 and pointer j for str2, while ensuring they remain within the bounds of the strings.
", "
If both str1[i] and str2[j] match, or if incrementing str1[i] matches str2[j], we increase both pointers; otherwise, we increment only pointer i.
", "
It is possible to make str2 a subsequence of str1 if j is at the end of str2, after we can no longer find a match.
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Most standard library headers are already included automatically for your convenience.

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OpenJDK 17. Java 8 features such as lambda expressions and stream API can be used.

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Most standard library headers are already included automatically for your convenience.

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Python 2.7.12.

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For Map/TreeMap data structure, you may use sortedcontainers library.

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Your code is compiled with level one optimization (-O1). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.

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Most standard library headers are already included automatically for your convenience.

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For hash table operations, you may use uthash. \\\"uthash.h\\\" is included by default. Below are some examples:

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3. Deleting an item in a hash:\\r\\n

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C# 10 with .NET 6 runtime

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Node.js 16.13.2.

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Ruby 3.1

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Some common data structure implementations are provided in the Algorithms module: https://www.rubydoc.info/github/kanwei/algorithms/Algorithms

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Go 1.18

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Python 3.10.

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Scala 2.13.7.

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Kotlin 1.3.10.

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Rust 1.58.1

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With bcmath module

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TypeScript 5.1.6, Node.js 16.13.2.

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Run with Racket 8.3.

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Dart 2.17.3

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