{ "data": { "question": { "questionId": "3795", "questionFrontendId": "3489", "categoryTitle": "Algorithms", "boundTopicId": 3611286, "title": "Zero Array Transformation IV", "titleSlug": "zero-array-transformation-iv", "content": "
You are given an integer array nums
of length n
and a 2D array queries
, where queries[i] = [li, ri, vali]
.
Each queries[i]
represents the following action on nums
:
[li, ri]
from nums
.vali
.A Zero Array is an array with all its elements equal to 0.
\n\nReturn the minimum possible non-negative value of k
, such that after processing the first k
queries in sequence, nums
becomes a Zero Array. If no such k
exists, return -1.
\n
Example 1:
\n\nInput: nums = [2,0,2], queries = [[0,2,1],[0,2,1],[1,1,3]]
\n\nOutput: 2
\n\nExplanation:
\n\n[0, 2]
by 1.[1, 0, 1]
.[0, 2]
by 1.[0, 0, 0]
, which is a Zero Array. Therefore, the minimum value of k
is 2.Example 2:
\n\nInput: nums = [4,3,2,1], queries = [[1,3,2],[0,2,1]]
\n\nOutput: -1
\n\nExplanation:
\n\nIt is impossible to make nums a Zero Array even after all the queries.
\nExample 3:
\n\nInput: nums = [1,2,3,2,1], queries = [[0,1,1],[1,2,1],[2,3,2],[3,4,1],[4,4,1]]
\n\nOutput: 4
\n\nExplanation:
\n\n[0, 1]
by 1
.[0, 1, 3, 2, 1]
.[1, 2]
by 1.[0, 0, 2, 2, 1]
.[2, 3]
by 2.[0, 0, 0, 0, 1]
.[0, 0, 0, 0, 0]
. Therefore, the minimum value of k
is 4.Example 4:
\n\nInput: nums = [1,2,3,2,6], queries = [[0,1,1],[0,2,1],[1,4,2],[4,4,4],[3,4,1],[4,4,5]]
\n\nOutput: 4
\n\n
Constraints:
\n\n1 <= nums.length <= 10
0 <= nums[i] <= 1000
1 <= queries.length <= 1000
queries[i] = [li, ri, vali]
0 <= li <= ri < nums.length
1 <= vali <= 10
给你一个长度为 n
的整数数组 nums
和一个二维数组 queries
,其中 queries[i] = [li, ri, vali]
。
每个 queries[i]
表示以下操作在 nums
上执行:
nums
中选择范围 [li, ri]
内的一个下标子集。vali
。零数组 是指所有元素都等于 0 的数组。
\n\n返回使得经过前 k
个查询(按顺序执行)后,nums
转变为 零数组 的最小可能 非负 值 k
。如果不存在这样的 k
,返回 -1。
数组的 子集 是指从数组中选择的一些元素(可能为空)。
\n\n\n\n
示例 1:
\n\n输入: nums = [2,0,2], queries = [[0,2,1],[0,2,1],[1,1,3]]
\n\n输出: 2
\n\n解释:
\n\n[0, 2]
的值减 1。[1, 0, 1]
。[0, 2]
的值减 1。[0, 0, 0]
,这就是一个零数组。因此,最小的 k
值为 2。示例 2:
\n\n输入: nums = [4,3,2,1], queries = [[1,3,2],[0,2,1]]
\n\n输出: -1
\n\n解释:
\n\n即使执行完所有查询,也无法使 nums
变为零数组。
示例 3:
\n\n输入: nums = [1,2,3,2,1], queries = [[0,1,1],[1,2,1],[2,3,2],[3,4,1],[4,4,1]]
\n\n输出: 4
\n\n解释:
\n\n[0, 1]
的值减 1。[0, 1, 3, 2, 1]
。[1, 2]
的值减 1。[0, 0, 2, 2, 1]
。[2, 3]
的值减 2。[0, 0, 0, 0, 1]
。4
的值减 1。[0, 0, 0, 0, 0]
。因此,最小的 k
值为 4。示例 4:
\n\n输入: nums = [1,2,3,2,6], queries = [[0,1,1],[0,2,1],[1,4,2],[4,4,4],[3,4,1],[4,4,5]]
\n\n输出: 4
\n\n\n
提示:
\n\n1 <= nums.length <= 10
0 <= nums[i] <= 1000
1 <= queries.length <= 1000
queries[i] = [li, ri, vali]
0 <= li <= ri < nums.length
1 <= vali <= 10
nums[i]
, use DP to check whether the queries[.][2]
values (i.e., the val
values) of the queries that affect it can form a combination with a sum equal to nums[i]
."
],
"solution": null,
"status": null,
"sampleTestCase": "[2,0,2]\n[[0,2,1],[0,2,1],[1,1,3]]",
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"judgeType": "large",
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