You are given an array nums consisting of positive integers.
Return the total frequencies of elements in nums such that those elements all have the maximum frequency.
The frequency of an element is the number of occurrences of that element in the array.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,2,2,3,1,4]\nOutput: 4\nExplanation: The elements 1 and 2 have a frequency of 2 which is the maximum frequency in the array.\nSo the number of elements in the array with maximum frequency is 4.\n\n\n
Example 2:
\n\n\nInput: nums = [1,2,3,4,5]\nOutput: 5\nExplanation: All elements of the array have a frequency of 1 which is the maximum.\nSo the number of elements in the array with maximum frequency is 5.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1001 <= nums[i] <= 100给你一个由 正整数 组成的数组 nums 。
返回数组 nums 中所有具有 最大 频率的元素的 总频率 。
元素的 频率 是指该元素在数组中出现的次数。
\n\n\n\n
示例 1：
\n\n\n输入：nums = [1,2,2,3,1,4]\n输出：4\n解释：元素 1 和 2 的频率为 2 ，是数组中的最大频率。\n因此具有最大频率的元素在数组中的数量是 4 。\n\n\n
示例 2：
\n\n\n输入：nums = [1,2,3,4,5]\n输出：5\n解释：数组中的所有元素的频率都为 1 ，是最大频率。\n因此具有最大频率的元素在数组中的数量是 5 。\n\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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