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            "questionId": "1907",
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            "title": "Count Pairs With XOR in a Range",
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            "content": "<p>Given a <strong>(0-indexed)</strong> integer array <code>nums</code> and two integers <code>low</code> and <code>high</code>, return <em>the number of <strong>nice pairs</strong></em>.</p>\r\n\r\n<p>A <strong>nice pair</strong> is a pair <code>(i, j)</code> where <code>0 &lt;= i &lt; j &lt; nums.length</code> and <code>low &lt;= (nums[i] XOR nums[j]) &lt;= high</code>.</p>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [1,4,2,7], low = 2, high = 6\r\n<strong>Output:</strong> 6\r\n<strong>Explanation:</strong> All nice pairs (i, j) are as follows:\r\n    - (0, 1): nums[0] XOR nums[1] = 5 \r\n    - (0, 2): nums[0] XOR nums[2] = 3\r\n    - (0, 3): nums[0] XOR nums[3] = 6\r\n    - (1, 2): nums[1] XOR nums[2] = 6\r\n    - (1, 3): nums[1] XOR nums[3] = 3\r\n    - (2, 3): nums[2] XOR nums[3] = 5\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [9,8,4,2,1], low = 5, high = 14\r\n<strong>Output:</strong> 8\r\n<strong>Explanation:</strong> All nice pairs (i, j) are as follows:\r\n​​​​​    - (0, 2): nums[0] XOR nums[2] = 13\r\n&nbsp;   - (0, 3): nums[0] XOR nums[3] = 11\r\n&nbsp;   - (0, 4): nums[0] XOR nums[4] = 8\r\n&nbsp;   - (1, 2): nums[1] XOR nums[2] = 12\r\n&nbsp;   - (1, 3): nums[1] XOR nums[3] = 10\r\n&nbsp;   - (1, 4): nums[1] XOR nums[4] = 9\r\n&nbsp;   - (2, 3): nums[2] XOR nums[3] = 6\r\n&nbsp;   - (2, 4): nums[2] XOR nums[4] = 5</pre>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Constraints:</strong></p>\r\n\r\n<ul>\r\n\t<li><code>1 &lt;= nums.length &lt;= 2 * 10<sup>4</sup></code></li>\r\n\t<li><code>1 &lt;= nums[i] &lt;= 2 * 10<sup>4</sup></code></li>\r\n\t<li><code>1 &lt;= low &lt;= high &lt;= 2 * 10<sup>4</sup></code></li>\r\n</ul>",
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                    "code": "class Solution {\npublic:\n    int countPairs(vector<int>& nums, int low, int high) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int countPairs(int[] nums, int low, int high) {\n        \n    }\n}",
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                    "code": "class Solution(object):\n    def countPairs(self, nums, low, high):\n        \"\"\"\n        :type nums: List[int]\n        :type low: int\n        :type high: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "/**\n * @param {number[]} nums\n * @param {number} low\n * @param {number} high\n * @return {number}\n */\nvar countPairs = function(nums, low, high) {\n    \n};",
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                    "code": "# @param {Integer[]} nums\n# @param {Integer} low\n# @param {Integer} high\n# @return {Integer}\ndef count_pairs(nums, low, high)\n    \nend",
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                    "code": "class Solution {\n    func countPairs(_ nums: [Int], _ low: Int, _ high: Int) -> Int {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn count_pairs(nums: Vec<i32>, low: i32, high: i32) -> i32 {\n        \n    }\n}",
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                    "code": "(define/contract (count-pairs nums low high)\n  (-> (listof exact-integer?) exact-integer? exact-integer? exact-integer?)\n\n  )",
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            "hints": [
                "Let's note that we can count all pairs with XOR ≤ K, so the answer would be to subtract the number of pairs withs XOR < low from the number of pairs with XOR ≤ high.",
                "For each value, find out the number of values when you XOR it with the result is  ≤ K using a trie."
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