There are n houses evenly lined up on the street, and each house is beautifully painted. You are given a 0-indexed integer array colors of length n, where colors[i] represents the color of the ith house.
Return the maximum distance between two houses with different colors.
\n\nThe distance between the ith and jth houses is abs(i - j), where abs(x) is the absolute value of x.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2021/10/31/eg1.png\")
\n\nInput: colors = [1,1,1,6,1,1,1]\nOutput: 3\nExplanation: In the above image, color 1 is blue, and color 6 is red.\nThe furthest two houses with different colors are house 0 and house 3.\nHouse 0 has color 1, and house 3 has color 6. The distance between them is abs(0 - 3) = 3.\nNote that houses 3 and 6 can also produce the optimal answer.\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2021/10/31/eg2.png\")
\n\nInput: colors = [1,8,3,8,3]\nOutput: 4\nExplanation: In the above image, color 1 is blue, color 8 is yellow, and color 3 is green.\nThe furthest two houses with different colors are house 0 and house 4.\nHouse 0 has color 1, and house 4 has color 3. The distance between them is abs(0 - 4) = 4.\n\n\n
Example 3:
\n\n\nInput: colors = [0,1]\nOutput: 1\nExplanation: The furthest two houses with different colors are house 0 and house 1.\nHouse 0 has color 0, and house 1 has color 1. The distance between them is abs(0 - 1) = 1.\n\n\n
\n
Constraints:
\n\nn == colors.length2 <= n <= 1000 <= colors[i] <= 100Compiled with clang 11 using the latest C++ 20 standard.
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