You are given a 0-indexed integer array nums, and an integer k.
The K-or of nums is a non-negative integer that satisfies the following:
ith bit is set in the K-or if and only if there are at least k elements of nums in which bit i is set.Return the K-or of nums.
Note that a bit i is set in x if (2i AND x) == 2i, where AND is the bitwise AND operator.
\n
Example 1:
\n\n\nInput: nums = [7,12,9,8,9,15], k = 4\nOutput: 9\nExplanation: Bit 0 is set at nums[0], nums[2], nums[4], and nums[5].\nBit 1 is set at nums[0], and nums[5].\nBit 2 is set at nums[0], nums[1], and nums[5].\nBit 3 is set at nums[1], nums[2], nums[3], nums[4], and nums[5].\nOnly bits 0 and 3 are set in at least k elements of the array, and bits i >= 4 are not set in any of the array's elements. Hence, the answer is 2^0 + 2^3 = 9.\n\n\n
Example 2:
\n\n\nInput: nums = [2,12,1,11,4,5], k = 6\nOutput: 0\nExplanation: Since k == 6 == nums.length, the 6-or of the array is equal to the bitwise AND of all its elements. Hence, the answer is 2 AND 12 AND 1 AND 11 AND 4 AND 5 = 0.\n\n\n
Example 3:
\n\n\nInput: nums = [10,8,5,9,11,6,8], k = 1\nOutput: 15\nExplanation: Since k == 1, the 1-or of the array is equal to the bitwise OR of all its elements. Hence, the answer is 10 OR 8 OR 5 OR 9 OR 11 OR 6 OR 8 = 15.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 500 <= nums[i] < 2311 <= k <= nums.lengthbit from the range [0, 31], then count the number of elements of nums that have bit set in them.",
"bit is set in integer x if and only if 2bit AND x == 2bit, where AND is the bitwise AND operation.",
"Fix a bit from the range [0, 31], then count the number of elements of nums that have bit set in them.",
"bit is set in integer x if and only if 2bit AND x == 2bit, where AND is the bitwise AND operation."
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