You are given an m x n grid. Each cell of grid represents a street. The street of grid[i][j] can be:
1 which means a street connecting the left cell and the right cell.2 which means a street connecting the upper cell and the lower cell.3 which means a street connecting the left cell and the lower cell.4 which means a street connecting the right cell and the lower cell.5 which means a street connecting the left cell and the upper cell.6 which means a street connecting the right cell and the upper cell.![\"\"](\"https://assets.leetcode.com/uploads/2020/03/05/main.png\")
\nYou will initially start at the street of the upper-left cell (0, 0). A valid path in the grid is a path that starts from the upper left cell (0, 0) and ends at the bottom-right cell (m - 1, n - 1). The path should only follow the streets.
Notice that you are not allowed to change any street.
\n\nReturn true if there is a valid path in the grid or false otherwise.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/03/05/e1.png\")
\n\nInput: grid = [[2,4,3],[6,5,2]]\nOutput: true\nExplanation: As shown you can start at cell (0, 0) and visit all the cells of the grid to reach (m - 1, n - 1).\n\n\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2020/03/05/e2.png\")
\n\nInput: grid = [[1,2,1],[1,2,1]]\nOutput: false\nExplanation: As shown you the street at cell (0, 0) is not connected with any street of any other cell and you will get stuck at cell (0, 0)\n\n\n
Example 3:
\n\n\nInput: grid = [[1,1,2]]\nOutput: false\nExplanation: You will get stuck at cell (0, 1) and you cannot reach cell (0, 2).\n\n\n
\n
Constraints:
\n\nm == grid.lengthn == grid[i].length1 <= m, n <= 3001 <= grid[i][j] <= 6Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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