{ "data": { "question": { "questionId": "1555", "questionFrontendId": "1444", "categoryTitle": "Algorithms", "boundTopicId": 235707, "title": "Number of Ways of Cutting a Pizza", "titleSlug": "number-of-ways-of-cutting-a-pizza", "content": "
Given a rectangular pizza represented as a rows x cols
matrix containing the following characters: 'A'
(an apple) and '.'
(empty cell) and given the integer k
. You have to cut the pizza into k
pieces using k-1
cuts.
For each cut you choose the direction: vertical or horizontal, then you choose a cut position at the cell boundary and cut the pizza into two pieces. If you cut the pizza vertically, give the left part of the pizza to a person. If you cut the pizza horizontally, give the upper part of the pizza to a person. Give the last piece of pizza to the last person.
\n\nReturn the number of ways of cutting the pizza such that each piece contains at least one apple. Since the answer can be a huge number, return this modulo 10^9 + 7.
\n\n\n
Example 1:
\n\n\n\n
\nInput: pizza = ["A..","AAA","..."], k = 3\nOutput: 3 \nExplanation: The figure above shows the three ways to cut the pizza. Note that pieces must contain at least one apple.\n\n\n
Example 2:
\n\n\nInput: pizza = ["A..","AA.","..."], k = 3\nOutput: 1\n\n\n
Example 3:
\n\n\nInput: pizza = ["A..","A..","..."], k = 1\nOutput: 1\n\n\n
\n
Constraints:
\n\n1 <= rows, cols <= 50
rows == pizza.length
cols == pizza[i].length
1 <= k <= 10
pizza
consists of characters 'A'
and '.'
only.给你一个 rows x cols
大小的矩形披萨和一个整数 k
,矩形包含两种字符: 'A'
(表示苹果)和 '.'
(表示空白格子)。你需要切披萨 k-1
次,得到 k
块披萨并送给别人。
切披萨的每一刀,先要选择是向垂直还是水平方向切,再在矩形的边界上选一个切的位置,将披萨一分为二。如果垂直地切披萨,那么需要把左边的部分送给一个人,如果水平地切,那么需要把上面的部分送给一个人。在切完最后一刀后,需要把剩下来的一块送给最后一个人。
\n\n请你返回确保每一块披萨包含 至少 一个苹果的切披萨方案数。由于答案可能是个很大的数字,请你返回它对 10^9 + 7 取余的结果。
\n\n\n\n
示例 1:
\n\n\n\n
输入:pizza = ["A..","AAA","..."], k = 3\n输出:3 \n解释:上图展示了三种切披萨的方案。注意每一块披萨都至少包含一个苹果。\n\n\n
示例 2:
\n\n输入:pizza = ["A..","AA.","..."], k = 3\n输出:1\n\n\n
示例 3:
\n\n输入:pizza = ["A..","A..","..."], k = 1\n输出:1\n\n\n
\n\n
提示:
\n\n1 <= rows, cols <= 50
rows == pizza.length
cols == pizza[i].length
1 <= k <= 10
pizza
只包含字符 'A'
和 '.'
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