You are given an integer n and an integer p in the range [0, n - 1]. Representing a 0-indexed array arr of length n where all positions are set to 0's, except position p which is set to 1.
You are also given an integer array banned containing some positions from the array. For the ith position in banned, arr[banned[i]] = 0, and banned[i] != p.
You can perform multiple operations on arr. In an operation, you can choose a subarray with size k and reverse the subarray. However, the 1 in arr should never go to any of the positions in banned. In other words, after each operation arr[banned[i]] remains 0.
Return an array ans where for each i from [0, n - 1], ans[i] is the minimum number of reverse operations needed to bring the 1 to position i in arr, or -1 if it is impossible.
ans[i] are independent for all i's.\n
Example 1:
\n\n\nInput: n = 4, p = 0, banned = [1,2], k = 4\nOutput: [0,-1,-1,1]\nExplanation: In this case\n\nk = 4so there is only one possible reverse operation we can perform, which is reversing the whole array. Initially, 1 is placed at position 0 so the amount of operations we need for position 0 is0. We can never place a 1 on the banned positions, so the answer for positions 1 and 2 is-1. Finally, with one reverse operation we can bring the 1 to index 3, so the answer for position 3 is1. \n
Example 2:
\n\n\nInput: n = 5, p = 0, banned = [2,4], k = 3\nOutput: [0,-1,-1,-1,-1]\nExplanation: In this case the 1 is initially at position 0, so the answer for that position is\n\n0. We can perform reverse operations of size 3. The 1 is currently located at position 0, so we need to reverse the subarray[0, 2]for it to leave that position, but reversing that subarray makes position 2 have a 1, which shouldn't happen. So, we can't move the 1 from position 0, making the result for all the other positions-1. \n
Example 3:
\n\n\nInput: n = 4, p = 2, banned = [0,1,3], k = 1\nOutput: [-1,-1,0,-1]\nExplanation: In this case we can only perform reverse operations of size 1. So the 1 never changes its position.\n\n\n
\n
Constraints:
\n\n1 <= n <= 1050 <= p <= n - 10 <= banned.length <= n - 10 <= banned[i] <= n - 11 <= k <= n banned[i] != pbanned are unique 给你一个整数 n 和一个在范围 [0, n - 1] 以内的整数 p ，它们表示一个长度为 n 且下标从 0 开始的数组 arr ，数组中除了下标为 p 处是 1 以外，其他所有数都是 0 。
同时给你一个整数数组 banned ，它包含数组中的一些位置。banned 中第 i 个位置表示 arr[banned[i]] = 0 ，题目保证 banned[i] != p 。
你可以对 arr 进行 若干次 操作。一次操作中，你选择大小为 k 的一个 子数组 ，并将它 翻转 。在任何一次翻转操作后，你都需要确保 arr 中唯一的 1 不会到达任何 banned 中的位置。换句话说，arr[banned[i]] 始终 保持 0 。
请你返回一个数组 ans ，对于 [0, n - 1] 之间的任意下标 i ，ans[i] 是将 1 放到位置 i 处的 最少 翻转操作次数，如果无法放到位置 i 处，此数为 -1 。
i ，ans[i] 相互之间独立计算。\n\n
示例 1：
\n\n\n输入：n = 4, p = 0, banned = [1,2], k = 4\n输出：[0,-1,-1,1]\n解释：k = 4，所以只有一种可行的翻转操作，就是将整个数组翻转。一开始 1 在位置 0 处，所以将它翻转到位置 0 处需要的操作数为 0 。\n我们不能将 1 翻转到 banned 中的位置，所以位置 1 和 2 处的答案都是 -1 。\n通过一次翻转操作，可以将 1 放到位置 3 处，所以位置 3 的答案是 1 。\n\n\n示例 2：
\n\n\n输入：n = 5, p = 0, banned = [2,4], k = 3\n输出：[0,-1,-1,-1,-1]\n解释：这个例子中 1 一开始在位置 0 处，所以此下标的答案为 0 。\n翻转的子数组长度为 k = 3 ，1 此时在位置 0 处，所以我们可以翻转子数组 [0, 2]，但翻转后的下标 2 在 banned 中，所以不能执行此操作。\n由于 1 没法离开位置 0 ，所以其他位置的答案都是 -1 。\n\n\n
示例 3：
\n\n\n输入：n = 4, p = 2, banned = [0,1,3], k = 1\n输出：[-1,-1,0,-1]\n解释：这个例子中，我们只能对长度为 1 的子数组执行翻转操作，所以 1 无法离开初始位置。\n\n\n
\n\n
提示：
\n\n1 <= n <= 1050 <= p <= n - 10 <= banned.length <= n - 10 <= banned[i] <= n - 11 <= k <= n banned[i] != pbanned 中的值 互不相同 。\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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