{ "data": { "question": { "questionId": "482", "questionFrontendId": "482", "categoryTitle": "Algorithms", "boundTopicId": 1850, "title": "License Key Formatting", "titleSlug": "license-key-formatting", "content": "
You are given a license key represented as a string s
that consists of only alphanumeric characters and dashes. The string is separated into n + 1
groups by n
dashes. You are also given an integer k
.
We want to reformat the string s
such that each group contains exactly k
characters, except for the first group, which could be shorter than k
but still must contain at least one character. Furthermore, there must be a dash inserted between two groups, and you should convert all lowercase letters to uppercase.
Return the reformatted license key.
\n\n\n
Example 1:
\n\n\nInput: s = "5F3Z-2e-9-w", k = 4\nOutput: "5F3Z-2E9W"\nExplanation: The string s has been split into two parts, each part has 4 characters.\nNote that the two extra dashes are not needed and can be removed.\n\n\n
Example 2:
\n\n\nInput: s = "2-5g-3-J", k = 2\nOutput: "2-5G-3J"\nExplanation: The string s has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 105
s
consists of English letters, digits, and dashes '-'
.1 <= k <= 104
给定一个许可密钥字符串 s
,仅由字母、数字字符和破折号组成。字符串由 n
个破折号分成 n + 1
组。你也会得到一个整数 k
。
我们想要重新格式化字符串 s
,使每一组包含 k
个字符,除了第一组,它可以比 k
短,但仍然必须包含至少一个字符。此外,两组之间必须插入破折号,并且应该将所有小写字母转换为大写字母。
返回 重新格式化的许可密钥 。
\n\n\n\n
示例 1:
\n\n\n输入:S = \"5F3Z-2e-9-w\", k = 4\n输出:\"5F3Z-2E9W\"\n解释:字符串 S 被分成了两个部分,每部分 4 个字符;\n 注意,两个额外的破折号需要删掉。\n\n\n
示例 2:
\n\n\n输入:S = \"2-5g-3-J\", k = 2\n输出:\"2-5G-3J\"\n解释:字符串 S 被分成了 3 个部分,按照前面的规则描述,第一部分的字符可以少于给定的数量,其余部分皆为 2 个字符。\n\n\n
\n\n
提示:
\n\n1 <= s.length <= 105
s
只包含字母、数字和破折号 '-'
.1 <= k <= 104
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use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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Python 2.7.12<\\/code><\\/p>\\r\\n\\r\\n
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"
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Python 3.10<\\/code><\\/p>\\r\\n\\r\\n
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Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n
rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n
PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n