{ "data": { "question": { "questionId": "988", "questionFrontendId": "951", "categoryTitle": "Algorithms", "boundTopicId": 2465, "title": "Flip Equivalent Binary Trees", "titleSlug": "flip-equivalent-binary-trees", "content": "

For a binary tree T, we can define a flip operation as follows: choose any node, and swap the left and right child subtrees.

\n\n

A binary tree X is flip equivalent to a binary tree Y if and only if we can make X equal to Y after some number of flip operations.

\n\n

Given the roots of two binary trees root1 and root2, return true if the two trees are flip equivalent or false otherwise.

\n\n

 

\n

Example 1:

\n\"Flipped\n
\nInput: root1 = [1,2,3,4,5,6,null,null,null,7,8], root2 = [1,3,2,null,6,4,5,null,null,null,null,8,7]\nOutput: true\nExplanation: We flipped at nodes with values 1, 3, and 5.\n
\n\n

Example 2:

\n\n
\nInput: root1 = [], root2 = []\nOutput: true\n
\n\n

Example 3:

\n\n
\nInput: root1 = [], root2 = [1]\nOutput: false\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "翻转等价二叉树", "translatedContent": "

我们可以为二叉树 T 定义一个 翻转操作 ，如下所示：选择任意节点，然后交换它的左子树和右子树。

\n\n

只要经过一定次数的翻转操作后，能使 X 等于 Y，我们就称二叉树 X 翻转 等价 于二叉树 Y。

\n\n

这些树由根节点 root1 和 root2 给出。如果两个二叉树是否是翻转 等价 的函数，则返回 true ，否则返回 false 。

\n\n

 

\n\n

示例 1：

\n\n

\"Flipped

\n\n
\n输入：root1 = [1,2,3,4,5,6,null,null,null,7,8], root2 = [1,3,2,null,6,4,5,null,null,null,null,8,7]\n输出：true\n解释：我们翻转值为 1，3 以及 5 的三个节点。\n
\n\n

示例 2:

\n\n
\n输入: root1 = [], root2 = []\n输出: true\n
\n\n

示例 3:

\n\n
\n输入: root1 = [], root2 = [1]\n输出: false\n
\n\n

 

\n\n

提示：

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0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root1\n * @param {TreeNode} root2\n * @return {boolean}\n */\nvar flipEquiv = function(root1, root2) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction flipEquiv(root1: TreeNode | null, root2: TreeNode | null): boolean {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root1\n * @param TreeNode $root2\n * @return Boolean\n */\n function flipEquiv($root1, $root2) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func flipEquiv(_ root1: TreeNode?, _ root2: TreeNode?) -> Bool {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun flipEquiv(root1: TreeNode?, root2: TreeNode?): Boolean {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n bool flipEquiv(TreeNode? root1, TreeNode? root2) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc flipEquiv(root1 *TreeNode, root2 *TreeNode) bool {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root1\n# @param {TreeNode} root2\n# @return {Boolean}\ndef flip_equiv(root1, root2)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def flipEquiv(root1: TreeNode, root2: TreeNode): Boolean = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option>>,\n// pub right: Option>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn flip_equiv(root1: Option>>, root2: Option>>) -> bool {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (flip-equiv root1 root2)\n (-> (or/c tree-node? #f) (or/c tree-node? #f) boolean?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec flip_equiv(Root1 :: #tree_node{} | null, Root2 :: #tree_node{} | null) -> boolean().\nflip_equiv(Root1, Root2) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec flip_equiv(root1 :: TreeNode.t | nil, root2 :: TreeNode.t | nil) :: boolean\n def flip_equiv(root1, root2) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"18.5K\", \"totalSubmission\": \"27.6K\", \"totalAcceptedRaw\": 18510, \"totalSubmissionRaw\": 27645, \"acRate\": \"67.0%\"}", "hints": [], "solution": null, "status": null, "sampleTestCase": "[1,2,3,4,5,6,null,null,null,7,8]\n[1,3,2,null,6,4,5,null,null,null,null,8,7]", "metaData": "{\r\n \"name\": \"flipEquiv\",\r\n \"params\": [\r\n {\r\n \"name\": \"root1\",\r\n \"type\": \"TreeNode\"\r\n },\r\n {\r\n \"name\": \"root2\",\r\n \"type\": \"TreeNode\"\r\n }\r\n ],\r\n \"return\": {\r\n \"type\": \"boolean\"\r\n }\r\n}\r\n", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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