{ "data": { "question": { "questionId": "3188", "questionFrontendId": "2923", "categoryTitle": "Algorithms", "boundTopicId": 2511414, "title": "Find Champion I", "titleSlug": "find-champion-i", "content": "
There are n
teams numbered from 0
to n - 1
in a tournament.
Given a 0-indexed 2D boolean matrix grid
of size n * n
. For all i, j
that 0 <= i, j <= n - 1
and i != j
team i
is stronger than team j
if grid[i][j] == 1
, otherwise, team j
is stronger than team i
.
Team a
will be the champion of the tournament if there is no team b
that is stronger than team a
.
Return the team that will be the champion of the tournament.
\n\n\n
Example 1:
\n\n\nInput: grid = [[0,1],[0,0]]\nOutput: 0\nExplanation: There are two teams in this tournament.\ngrid[0][1] == 1 means that team 0 is stronger than team 1. So team 0 will be the champion.\n\n\n
Example 2:
\n\n\nInput: grid = [[0,0,1],[1,0,1],[0,0,0]]\nOutput: 1\nExplanation: There are three teams in this tournament.\ngrid[1][0] == 1 means that team 1 is stronger than team 0.\ngrid[1][2] == 1 means that team 1 is stronger than team 2.\nSo team 1 will be the champion.\n\n\n
\n
Constraints:
\n\nn == grid.length
n == grid[i].length
2 <= n <= 100
grid[i][j]
is either 0
or 1
.i grid[i][i]
is 0.
i, j
that i != j
, grid[i][j] != grid[j][i]
.a
is stronger than team b
and team b
is stronger than team c
, then team a
is stronger than team c
.一场比赛中共有 n
支队伍,按从 0
到 n - 1
编号。
给你一个下标从 0 开始、大小为 n * n
的二维布尔矩阵 grid
。对于满足 0 <= i, j <= n - 1
且 i != j
的所有 i, j
:如果 grid[i][j] == 1
,那么 i
队比 j
队 强 ;否则,j
队比 i
队 强 。
在这场比赛中,如果不存在某支强于 a
队的队伍,则认为 a
队将会是 冠军 。
返回这场比赛中将会成为冠军的队伍。
\n\n\n\n
示例 1:
\n\n\n输入:grid = [[0,1],[0,0]]\n输出:0\n解释:比赛中有两支队伍。\ngrid[0][1] == 1 表示 0 队比 1 队强。所以 0 队是冠军。\n\n\n
示例 2:
\n\n\n输入:grid = [[0,0,1],[1,0,1],[0,0,0]]\n输出:1\n解释:比赛中有三支队伍。\ngrid[1][0] == 1 表示 1 队比 0 队强。\ngrid[1][2] == 1 表示 1 队比 2 队强。\n所以 1 队是冠军。\n\n\n
\n\n
提示:
\n\nn == grid.length
n == grid[i].length
2 <= n <= 100
grid[i][j]
的值为 0
或 1
i
, grid[i][i]
等于 0.
i != j
的所有 i, j
,grid[i][j] != grid[j][i]
均成立a
队比 b
队强,b
队比 c
队强,那么 a
队比 c
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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Python 2.7.12<\\/code><\\/p>\\r\\n\\r\\n
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n
PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n