Hercy wants to save money for his first car. He puts money in the Leetcode bank every day.
\n\nHe starts by putting in $1 on Monday, the first day. Every day from Tuesday to Sunday, he will put in $1 more than the day before. On every subsequent Monday, he will put in $1 more than the previous Monday.
Given n, return the total amount of money he will have in the Leetcode bank at the end of the nth day.
\n
Example 1:
\n\n\nInput: n = 4\nOutput: 10\nExplanation: After the 4th day, the total is 1 + 2 + 3 + 4 = 10.\n\n\n
Example 2:
\n\n\nInput: n = 10\nOutput: 37\nExplanation: After the 10th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4) = 37. Notice that on the 2nd Monday, Hercy only puts in $2.\n\n\n
Example 3:
\n\n\nInput: n = 20\nOutput: 96\nExplanation: After the 20th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4 + 5 + 6 + 7 + 8) + (3 + 4 + 5 + 6 + 7 + 8) = 96.\n\n\n
\n
Constraints:
\n\n1 <= n <= 1000Hercy 想要为购买第一辆车存钱。他 每天 都往力扣银行里存钱。
\n\n最开始，他在周一的时候存入 1 块钱。从周二到周日，他每天都比前一天多存入 1 块钱。在接下来每一个周一，他都会比 前一个周一 多存入 1 块钱。
给你 n ，请你返回在第 n 天结束的时候他在力扣银行总共存了多少块钱。
\n\n
示例 1：
\n\n输入：n = 4\n输出：10\n解释：第 4 天后，总额为 1 + 2 + 3 + 4 = 10 。\n\n\n
示例 2：
\n\n输入：n = 10\n输出：37\n解释：第 10 天后，总额为 (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4) = 37 。注意到第二个星期一，Hercy 存入 2 块钱。\n\n\n
示例 3：
\n\n输入：n = 20\n输出：96\n解释：第 20 天后，总额为 (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4 + 5 + 6 + 7 + 8) + (3 + 4 + 5 + 6 + 7 + 8) = 96 。\n\n\n
\n\n
提示：
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