{ "data": { "question": { "questionId": "3105", "questionFrontendId": "2858", "boundTopicId": null, "title": "Minimum Edge Reversals So Every Node Is Reachable", "titleSlug": "minimum-edge-reversals-so-every-node-is-reachable", "content": "
There is a simple directed graph with n
nodes labeled from 0
to n - 1
. The graph would form a tree if its edges were bi-directional.
You are given an integer n
and a 2D integer array edges
, where edges[i] = [ui, vi]
represents a directed edge going from node ui
to node vi
.
An edge reversal changes the direction of an edge, i.e., a directed edge going from node ui
to node vi
becomes a directed edge going from node vi
to node ui
.
For every node i
in the range [0, n - 1]
, your task is to independently calculate the minimum number of edge reversals required so it is possible to reach any other node starting from node i
through a sequence of directed edges.
Return an integer array answer
, where answer[i]
is the minimum number of edge reversals required so it is possible to reach any other node starting from node i
through a sequence of directed edges.
\n
Example 1:
\n\n\n\n\nInput: n = 4, edges = [[2,0],[2,1],[1,3]]\nOutput: [1,1,0,2]\nExplanation: The image above shows the graph formed by the edges.\nFor node 0: after reversing the edge [2,0], it is possible to reach any other node starting from node 0.\nSo, answer[0] = 1.\nFor node 1: after reversing the edge [2,1], it is possible to reach any other node starting from node 1.\nSo, answer[1] = 1.\nFor node 2: it is already possible to reach any other node starting from node 2.\nSo, answer[2] = 0.\nFor node 3: after reversing the edges [1,3] and [2,1], it is possible to reach any other node starting from node 3.\nSo, answer[3] = 2.\n\n\n
Example 2:
\n\n\n\n\nInput: n = 3, edges = [[1,2],[2,0]]\nOutput: [2,0,1]\nExplanation: The image above shows the graph formed by the edges.\nFor node 0: after reversing the edges [2,0] and [1,2], it is possible to reach any other node starting from node 0.\nSo, answer[0] = 2.\nFor node 1: it is already possible to reach any other node starting from node 1.\nSo, answer[1] = 0.\nFor node 2: after reversing the edge [1, 2], it is possible to reach any other node starting from node 2.\nSo, answer[2] = 1.\n\n\n
\n
Constraints:
\n\n2 <= n <= 105
edges.length == n - 1
edges[i].length == 2
0 <= ui == edges[i][0] < n
0 <= vi == edges[i][1] < n
ui != vi
0
as the root, let dp[x]
be the minimum number of edge reversals so node x
can reach every node in its subtree.",
"Using a DFS traversing the edges bidirectionally, we can compute dp
.dp[x] = dp[y] +
(1
if the edge between x
and y
is going from y
to x
; 0
otherwise), where x
is the parent of y
.",
"Let answer[x]
be the minimum number of edge reversals so it is possible to reach any other node starting from node x
.",
"Using another DFS starting from node 0
and traversing the edges bidirectionally, we can compute answer
.answer[0] = dp[0]
answer[y] = answer[x] +
(1
if the edge between x
and y
is going from x
to y
; -1
otherwise), where x
is the parent of y
."
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