{ "data": { "question": { "questionId": "572", "questionFrontendId": "572", "categoryTitle": "Algorithms", "boundTopicId": 1702, "title": "Subtree of Another Tree", "titleSlug": "subtree-of-another-tree", "content": "

Given the roots of two binary trees root and subRoot, return true if there is a subtree of root with the same structure and node values of subRoot and false otherwise.

\n\n

A subtree of a binary tree tree is a tree that consists of a node in tree and all of this node's descendants. The tree tree could also be considered as a subtree of itself.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: root = [3,4,5,1,2], subRoot = [4,1,2]\nOutput: true\n
\n\n

Example 2:

\n\"\"\n
\nInput: root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2]\nOutput: false\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "另一棵树的子树", "translatedContent": "
\n
\n

给你两棵二叉树 rootsubRoot 。检验 root 中是否包含和 subRoot 具有相同结构和节点值的子树。如果存在,返回 true ;否则,返回 false

\n\n

二叉树 tree 的一棵子树包括 tree 的某个节点和这个节点的所有后代节点。tree 也可以看做它自身的一棵子树。

\n\n

 

\n\n

示例 1:

\n\"\"\n
\n输入:root = [3,4,5,1,2], subRoot = [4,1,2]\n输出:true\n
\n\n

示例 2:

\n\"\"\n
\n输入:root = [3,4,5,1,2,null,null,null,null,0], subRoot = [4,1,2]\n输出:false\n
\n\n

 

\n\n

提示:

\n\n\n
\n
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0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {TreeNode} subRoot\n * @return {boolean}\n */\nvar isSubtree = function(root, subRoot) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {TreeNode} sub_root\n# @return {Boolean}\ndef is_subtree(root, sub_root)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func isSubtree(_ root: TreeNode?, _ subRoot: TreeNode?) -> Bool {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc isSubtree(root *TreeNode, subRoot *TreeNode) bool {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def isSubtree(root: TreeNode, subRoot: TreeNode): Boolean = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun isSubtree(root: TreeNode?, subRoot: TreeNode?): Boolean {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option>>,\n// pub right: Option>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn is_subtree(root: Option>>, sub_root: Option>>) -> bool {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param TreeNode $subRoot\n * @return Boolean\n */\n function isSubtree($root, $subRoot) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction isSubtree(root: TreeNode | null, subRoot: TreeNode | null): boolean {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (is-subtree root subRoot)\n (-> (or/c tree-node? #f) (or/c tree-node? #f) boolean?)\n\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec is_subtree(Root :: #tree_node{} | null, SubRoot :: #tree_node{} | null) -> boolean().\nis_subtree(Root, SubRoot) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec is_subtree(root :: TreeNode.t | nil, sub_root :: TreeNode.t | nil) :: boolean\n def is_subtree(root, sub_root) do\n\n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"111.2K\", \"totalSubmission\": \"234.5K\", \"totalAcceptedRaw\": 111241, \"totalSubmissionRaw\": 234504, \"acRate\": \"47.4%\"}", "hints": [ "Which approach is better here- recursive or iterative?", "If recursive approach is better, can you write recursive function with its parameters?", "Two trees s and t are said to be identical if their root values are same and their left and right subtrees are identical. Can you write this in form of recursive formulae?", "Recursive formulae can be: \r\nisIdentical(s,t)= s.val==t.val AND isIdentical(s.left,t.left) AND isIdentical(s.right,t.right)" ], "solution": null, "status": null, "sampleTestCase": "[3,4,5,1,2]\n[4,1,2]", "metaData": "{\n \"name\": \"isSubtree\",\n \"params\": [\n {\n \"name\": \"root\",\n \"type\": \"TreeNode\"\n },\n {\n \"name\": \"subRoot\",\n \"type\": \"TreeNode\"\n }\n ],\n \"return\": {\n \"type\": \"boolean\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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TypeScript 4.5.4<\\/p>\\r\\n\\r\\n

Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2020<\\/p>\"],\"racket\":[\"Racket\",\"

Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n

\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n

\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}", "book": null, "isSubscribed": false, "isDailyQuestion": false, "dailyRecordStatus": null, "editorType": "CKEDITOR", "ugcQuestionId": null, "style": "LEETCODE", "exampleTestcases": "[3,4,5,1,2]\n[4,1,2]\n[3,4,5,1,2,null,null,null,null,0]\n[4,1,2]", "__typename": "QuestionNode" } } }