{ "data": { "question": { "questionId": "671", "questionFrontendId": "671", "categoryTitle": "Algorithms", "boundTopicId": 1596, "title": "Second Minimum Node In a Binary Tree", "titleSlug": "second-minimum-node-in-a-binary-tree", "content": "
Given a non-empty special binary tree consisting of nodes with the non-negative value, where each node in this tree has exactly two
or zero
sub-node. If the node has two sub-nodes, then this node's value is the smaller value among its two sub-nodes. More formally, the property root.val = min(root.left.val, root.right.val)
always holds.
Given such a binary tree, you need to output the second minimum value in the set made of all the nodes' value in the whole tree.
\n\nIf no such second minimum value exists, output -1 instead.
\n\n\n\n
\n
Example 1:
\n\n\nInput: root = [2,2,5,null,null,5,7]\nOutput: 5\nExplanation: The smallest value is 2, the second smallest value is 5.\n\n\n
Example 2:
\n\n\nInput: root = [2,2,2]\nOutput: -1\nExplanation: The smallest value is 2, but there isn't any second smallest value.\n\n\n
\n
Constraints:
\n\n[1, 25]
.1 <= Node.val <= 231 - 1
root.val == min(root.left.val, root.right.val)
for each internal node of the tree.给定一个非空特殊的二叉树,每个节点都是正数,并且每个节点的子节点数量只能为 2
或 0
。如果一个节点有两个子节点的话,那么该节点的值等于两个子节点中较小的一个。
更正式地说,即 root.val = min(root.left.val, root.right.val)
总成立。
给出这样的一个二叉树,你需要输出所有节点中的 第二小的值 。
\n\n如果第二小的值不存在的话,输出 -1 。
\n\n\n\n
示例 1:
\n\n\n输入:root = [2,2,5,null,null,5,7]\n输出:5\n解释:最小的值是 2 ,第二小的值是 5 。\n\n\n
示例 2:
\n\n\n输入:root = [2,2,2]\n输出:-1\n解释:最小的值是 2, 但是不存在第二小的值。\n\n\n
\n\n
提示:
\n\n[1, 25]
内1 <= Node.val <= 231 - 1
root.val == min(root.left.val, root.right.val)
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