{ "data": { "question": { "questionId": "936", "questionFrontendId": "900", "categoryTitle": "Algorithms", "boundTopicId": 1240, "title": "RLE Iterator", "titleSlug": "rle-iterator", "content": "

We can use run-length encoding (i.e., RLE) to encode a sequence of integers. In a run-length encoded array of even length encoding (0-indexed), for all even i, encoding[i] tells us the number of times that the non-negative integer value encoding[i + 1] is repeated in the sequence.

\n\n\n\n

Given a run-length encoded array, design an iterator that iterates through it.

\n\n

Implement the RLEIterator class:

\n\n\n\n

 

\n

Example 1:

\n\n
\nInput\n["RLEIterator", "next", "next", "next", "next"]\n[[[3, 8, 0, 9, 2, 5]], [2], [1], [1], [2]]\nOutput\n[null, 8, 8, 5, -1]\n\nExplanation\nRLEIterator rLEIterator = new RLEIterator([3, 8, 0, 9, 2, 5]); // This maps to the sequence [8,8,8,5,5].\nrLEIterator.next(2); // exhausts 2 terms of the sequence, returning 8. The remaining sequence is now [8, 5, 5].\nrLEIterator.next(1); // exhausts 1 term of the sequence, returning 8. The remaining sequence is now [5, 5].\nrLEIterator.next(1); // exhausts 1 term of the sequence, returning 5. The remaining sequence is now [5].\nrLEIterator.next(2); // exhausts 2 terms, returning -1. This is because the first term exhausted was 5,\nbut the second term did not exist. Since the last term exhausted does not exist, we return -1.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "RLE 迭代器", "translatedContent": "

我们可以使用游程编码(即 RLE )来编码一个整数序列。在偶数长度 encoding ( 从 0 开始 )的游程编码数组中，对于所有偶数 i ，encoding[i] 告诉我们非负整数 encoding[i + 1] 在序列中重复的次数。

\n\n\n\n

给定一个游程长度的编码数组，设计一个迭代器来遍历它。

\n\n

实现 RLEIterator 类:

\n\n\n\n

 

\n\n

示例 1：

\n\n
\n输入：\n[\"RLEIterator\",\"next\",\"next\",\"next\",\"next\"]\n[[[3,8,0,9,2,5]],[2],[1],[1],[2]]\n输出：\n[null,8,8,5,-1]\n解释：\nRLEIterator rLEIterator = new RLEIterator([3, 8, 0, 9, 2, 5]); // 这映射到序列 [8,8,8,5,5]。\nrLEIterator.next(2); // 耗去序列的 2 个项，返回 8。现在剩下的序列是 [8, 5, 5]。\nrLEIterator.next(1); // 耗去序列的 1 个项，返回 8。现在剩下的序列是 [5, 5]。\nrLEIterator.next(1); // 耗去序列的 1 个项，返回 5。现在剩下的序列是 [5]。\nrLEIterator.next(2); // 耗去序列的 2 个项，返回 -1。 这是由于第一个被耗去的项是 5，\n但第二个项并不存在。由于最后一个要耗去的项不存在，我们返回 -1。\n
\n\n

 

\n\n

提示：

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"TopicTagNode" } ], "companyTagStats": null, "codeSnippets": [ { "lang": "C++", "langSlug": "cpp", "code": "class RLEIterator {\npublic:\n RLEIterator(vector& encoding) {\n\n }\n \n int next(int n) {\n\n }\n};\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * RLEIterator* obj = new RLEIterator(encoding);\n * int param_1 = obj->next(n);\n */", "__typename": "CodeSnippetNode" }, { "lang": "Java", "langSlug": "java", "code": "class RLEIterator {\n\n public RLEIterator(int[] encoding) {\n\n }\n \n public int next(int n) {\n\n }\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * RLEIterator obj = new RLEIterator(encoding);\n * int param_1 = obj.next(n);\n */", "__typename": "CodeSnippetNode" }, { "lang": "Python", "langSlug": "python", "code": "class RLEIterator(object):\n\n def __init__(self, encoding):\n \"\"\"\n :type encoding: List[int]\n \"\"\"\n\n\n def next(self, n):\n \"\"\"\n :type n: int\n :rtype: int\n \"\"\"\n\n\n\n# Your RLEIterator object will be instantiated and called as such:\n# obj = RLEIterator(encoding)\n# param_1 = obj.next(n)", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "class RLEIterator:\n\n def __init__(self, encoding: List[int]):\n\n\n def next(self, n: int) -> int:\n\n\n\n# Your RLEIterator object will be instantiated and called as such:\n# obj = RLEIterator(encoding)\n# param_1 = obj.next(n)", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "\n\n\ntypedef struct {\n\n} RLEIterator;\n\n\nRLEIterator* rLEIteratorCreate(int* encoding, int encodingSize) {\n\n}\n\nint rLEIteratorNext(RLEIterator* obj, int n) {\n\n}\n\nvoid rLEIteratorFree(RLEIterator* obj) {\n\n}\n\n/**\n * Your RLEIterator struct will be instantiated and called as such:\n * RLEIterator* obj = rLEIteratorCreate(encoding, encodingSize);\n * int param_1 = rLEIteratorNext(obj, n);\n \n * rLEIteratorFree(obj);\n*/", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "public class RLEIterator {\n\n public RLEIterator(int[] encoding) {\n\n }\n \n public int Next(int n) {\n\n }\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * RLEIterator obj = new RLEIterator(encoding);\n * int param_1 = obj.Next(n);\n */", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number[]} encoding\n */\nvar RLEIterator = function(encoding) {\n\n};\n\n/** \n * @param {number} n\n * @return {number}\n */\nRLEIterator.prototype.next = function(n) {\n\n};\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * var obj = new RLEIterator(encoding)\n * var param_1 = obj.next(n)\n */", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "class RLEIterator\n\n=begin\n :type encoding: Integer[]\n=end\n def initialize(encoding)\n\n end\n\n\n=begin\n :type n: Integer\n :rtype: Integer\n=end\n def next(n)\n\n end\n\n\nend\n\n# Your RLEIterator object will be instantiated and called as such:\n# obj = RLEIterator.new(encoding)\n# param_1 = obj.next(n)", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "\nclass RLEIterator {\n\n init(_ encoding: [Int]) {\n\n }\n \n func next(_ n: Int) -> Int {\n\n }\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * let obj = RLEIterator(encoding)\n * let ret_1: Int = obj.next(n)\n */", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "type RLEIterator struct {\n\n}\n\n\nfunc Constructor(encoding []int) RLEIterator {\n\n}\n\n\nfunc (this *RLEIterator) Next(n int) int {\n\n}\n\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * obj := Constructor(encoding);\n * param_1 := obj.Next(n);\n */", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "class RLEIterator(_encoding: Array[Int]) {\n\n def next(n: Int): Int = {\n\n }\n\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * var obj = new RLEIterator(encoding)\n * var param_1 = obj.next(n)\n */", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class RLEIterator(encoding: IntArray) {\n\n fun next(n: Int): Int {\n\n }\n\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * var obj = RLEIterator(encoding)\n * var param_1 = obj.next(n)\n */", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "struct RLEIterator {\n\n}\n\n\n/**\n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl RLEIterator {\n\n fn new(encoding: Vec) -> Self {\n\n }\n \n fn next(&self, n: i32) -> i32 {\n\n }\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * let obj = RLEIterator::new(encoding);\n * let ret_1: i32 = obj.next(n);\n */", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "class RLEIterator {\n /**\n * @param Integer[] $encoding\n */\n function __construct($encoding) {\n\n }\n\n /**\n * @param Integer $n\n * @return Integer\n */\n function next($n) {\n\n }\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * $obj = RLEIterator($encoding);\n * $ret_1 = $obj->next($n);\n */", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "class RLEIterator {\n constructor(encoding: number[]) {\n\n }\n\n next(n: number): number {\n\n }\n}\n\n/**\n * Your RLEIterator object will be instantiated and called as such:\n * var obj = new RLEIterator(encoding)\n * var param_1 = obj.next(n)\n */", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define rle-iterator%\n (class object%\n (super-new)\n\n ; encoding : (listof exact-integer?)\n (init-field\n encoding)\n \n ; 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end\nend\n\n# Your functions will be called as such:\n# RLEIterator.init_(encoding)\n# param_1 = RLEIterator.next(n)\n\n# RLEIterator.init_ will be called before every test case, in which you can do some necessary initializations.", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"4K\", \"totalSubmission\": \"8K\", \"totalAcceptedRaw\": 4013, \"totalSubmissionRaw\": 8000, \"acRate\": \"50.2%\"}", "hints": [], "solution": null, "status": null, "sampleTestCase": "[\"RLEIterator\",\"next\",\"next\",\"next\",\"next\"]\n[[[3,8,0,9,2,5]],[2],[1],[1],[2]]", "metaData": "{\n \"classname\": \"RLEIterator\",\n \"maxbytesperline\": 200000,\n \"constructor\": {\n \"params\": [\n {\n \"type\": \"integer[]\",\n \"name\": \"encoding\"\n }\n ]\n },\n \"methods\": [\n {\n \"name\": \"next\",\n \"params\": [\n {\n \"type\": \"integer\",\n \"name\": \"n\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n }\n ],\n \"systemdesign\": true,\n \"params\": [\n {\n \"name\": 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Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n
\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n
\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}",
            "book": null,
            "isSubscribed": false,
            "isDailyQuestion": false,
            "dailyRecordStatus": null,
            "editorType": "CKEDITOR",
            "ugcQuestionId": null,
            "style": "LEETCODE",
            "exampleTestcases": "[\"RLEIterator\",\"next\",\"next\",\"next\",\"next\"]\n[[[3,8,0,9,2,5]],[2],[1],[1],[2]]",
            "__typename": "QuestionNode"
        }
    }
}