{ "data": { "question": { "questionId": "2229", "questionFrontendId": "2106", "categoryTitle": "Algorithms", "boundTopicId": 1149412, "title": "Maximum Fruits Harvested After at Most K Steps", "titleSlug": "maximum-fruits-harvested-after-at-most-k-steps", "content": "

Fruits are available at some positions on an infinite x-axis. You are given a 2D integer array fruits where fruits[i] = [positioni, amounti] depicts amounti fruits at the position positioni. fruits is already sorted by positioni in ascending order, and each positioni is unique.

\n\n

You are also given an integer startPos and an integer k. Initially, you are at the position startPos. From any position, you can either walk to the left or right. It takes one step to move one unit on the x-axis, and you can walk at most k steps in total. For every position you reach, you harvest all the fruits at that position, and the fruits will disappear from that position.

\n\n

Return the maximum total number of fruits you can harvest.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: fruits = [[2,8],[6,3],[8,6]], startPos = 5, k = 4\nOutput: 9\nExplanation: \nThe optimal way is to:\n- Move right to position 6 and harvest 3 fruits\n- Move right to position 8 and harvest 6 fruits\nYou moved 3 steps and harvested 3 + 6 = 9 fruits in total.\n
\n\n

Example 2:

\n\"\"\n
\nInput: fruits = [[0,9],[4,1],[5,7],[6,2],[7,4],[10,9]], startPos = 5, k = 4\nOutput: 14\nExplanation: \nYou can move at most k = 4 steps, so you cannot reach position 0 nor 10.\nThe optimal way is to:\n- Harvest the 7 fruits at the starting position 5\n- Move left to position 4 and harvest 1 fruit\n- Move right to position 6 and harvest 2 fruits\n- Move right to position 7 and harvest 4 fruits\nYou moved 1 + 3 = 4 steps and harvested 7 + 1 + 2 + 4 = 14 fruits in total.\n
\n\n

Example 3:

\n\"\"\n
\nInput: fruits = [[0,3],[6,4],[8,5]], startPos = 3, k = 2\nOutput: 0\nExplanation:\nYou can move at most k = 2 steps and cannot reach any position with fruits.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "摘水果", "translatedContent": "

在一个无限的 x 坐标轴上,有许多水果分布在其中某些位置。给你一个二维整数数组 fruits ,其中 fruits[i] = [positioni, amounti] 表示共有 amounti 个水果放置在 positioni 上。fruits 已经按 positioni 升序排列 ,每个 positioni 互不相同

\n\n

另给你两个整数 startPosk 。最初,你位于 startPos 。从任何位置,你可以选择 向左或者向右 走。在 x 轴上每移动 一个单位 ,就记作 一步 。你总共可以走 最多 k 步。你每达到一个位置,都会摘掉全部的水果,水果也将从该位置消失(不会再生)。

\n\n

返回你可以摘到水果的 最大总数

\n\n

 

\n\n

示例 1:

\n\"\"\n
输入:fruits = [[2,8],[6,3],[8,6]], startPos = 5, k = 4\n输出:9\n解释:\n最佳路线为:\n- 向右移动到位置 6 ,摘到 3 个水果\n- 向右移动到位置 8 ,摘到 6 个水果\n移动 3 步,共摘到 3 + 6 = 9 个水果\n
\n\n

示例 2:

\n\"\"\n
输入:fruits = [[0,9],[4,1],[5,7],[6,2],[7,4],[10,9]], startPos = 5, k = 4\n输出:14\n解释:\n可以移动最多 k = 4 步,所以无法到达位置 0 和位置 10 。\n最佳路线为:\n- 在初始位置 5 ,摘到 7 个水果\n- 向左移动到位置 4 ,摘到 1 个水果\n- 向右移动到位置 6 ,摘到 2 个水果\n- 向右移动到位置 7 ,摘到 4 个水果\n移动 1 + 3 = 4 步,共摘到 7 + 1 + 2 + 4 = 14 个水果\n
\n\n

示例 3:

\n\"\"\n
输入:fruits = [[0,3],[6,4],[8,5]], startPos = 3, k = 2\n输出:0\n解释:\n最多可以移动 k = 2 步,无法到达任一有水果的地方\n
\n\n

 

\n\n

提示:

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exact-integer? exact-integer?)\n\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec max_total_fruits(Fruits :: [[integer()]], StartPos :: integer(), K :: integer()) -> integer().\nmax_total_fruits(Fruits, StartPos, K) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec max_total_fruits(fruits :: [[integer]], start_pos :: integer, k :: integer) :: integer\n def max_total_fruits(fruits, start_pos, k) do\n\n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"3.6K\", \"totalSubmission\": \"11.1K\", \"totalAcceptedRaw\": 3637, \"totalSubmissionRaw\": 11123, \"acRate\": \"32.7%\"}", "hints": [ "Does an optimal path have very few patterns? For example, could a path that goes left, turns and goes right, then turns again and goes left be any better than a path that simply goes left, turns, and goes right?", "The optimal path turns at most once. That is, the optimal path is one of these: to go left only; to go right only; to go left, turn and go right; or to go right, turn and go left.", "Moving x steps left then k-x steps right gives you a range of positions that you can reach.", "Use prefix sums to get the sum of all fruits for each possible range.", "Use a similar strategy for all the paths that go right, then turn and go left." ], "solution": null, "status": null, "sampleTestCase": "[[2,8],[6,3],[8,6]]\n5\n4", "metaData": "{\n \"name\": \"maxTotalFruits\",\n \"params\": [\n {\n \"name\": \"fruits\",\n \"type\": \"integer[][]\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"startPos\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"k\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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