You are given an array of integers stones where stones[i] is the weight of the ith stone.
We are playing a game with the stones. On each turn, we choose the heaviest two stones and smash them together. Suppose the heaviest two stones have weights x and y with x <= y. The result of this smash is:
x == y, both stones are destroyed, andx != y, the stone of weight x is destroyed, and the stone of weight y has new weight y - x.At the end of the game, there is at most one stone left.
\n\nReturn the smallest possible weight of the left stone. If there are no stones left, return 0.
\n
Example 1:
\n\n\nInput: stones = [2,7,4,1,8,1]\nOutput: 1\nExplanation: \nWe combine 7 and 8 to get 1 so the array converts to [2,4,1,1,1] then,\nwe combine 2 and 4 to get 2 so the array converts to [2,1,1,1] then,\nwe combine 2 and 1 to get 1 so the array converts to [1,1,1] then,\nwe combine 1 and 1 to get 0 so the array converts to [1] then that's the value of the last stone.\n\n\n
Example 2:
\n\n\nInput: stones = [1]\nOutput: 1\n\n\n
\n
Constraints:
\n\n1 <= stones.length <= 301 <= stones[i] <= 1000有一堆石头，每块石头的重量都是正整数。
\n\n每一回合，从中选出两块 最重的 石头，然后将它们一起粉碎。假设石头的重量分别为 x 和 y，且 x <= y。那么粉碎的可能结果如下：
x == y，那么两块石头都会被完全粉碎；x != y，那么重量为 x 的石头将会完全粉碎，而重量为 y 的石头新重量为 y-x。最后，最多只会剩下一块石头。返回此石头的重量。如果没有石头剩下，就返回 0。
\n\n
示例：
\n\n\n输入：[2,7,4,1,8,1]\n输出：1\n解释：\n先选出 7 和 8，得到 1，所以数组转换为 [2,4,1,1,1]，\n再选出 2 和 4，得到 2，所以数组转换为 [2,1,1,1]，\n接着是 2 和 1，得到 1，所以数组转换为 [1,1,1]，\n最后选出 1 和 1，得到 0，最终数组转换为 [1]，这就是最后剩下那块石头的重量。\n\n
\n\n
提示：
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