{ "data": { "question": { "questionId": "2274", "questionFrontendId": "2154", "categoryTitle": "Algorithms", "boundTopicId": 1235806, "title": "Keep Multiplying Found Values by Two", "titleSlug": "keep-multiplying-found-values-by-two", "content": "

You are given an array of integers nums. You are also given an integer original which is the first number that needs to be searched for in nums.

\n\n

You then do the following steps:

\n\n
    \n\t
  1. If original is found in nums, multiply it by two (i.e., set original = 2 * original).
    2. \n\t
  2. Otherwise, stop the process.
    3. \n\t
  3. Repeat this process with the new number as long as you keep finding the number.
    4. \n
\n\n

Return the final value of original.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [5,3,6,1,12], original = 3\nOutput: 24\nExplanation: \n- 3 is found in nums. 3 is multiplied by 2 to obtain 6.\n- 6 is found in nums. 6 is multiplied by 2 to obtain 12.\n- 12 is found in nums. 12 is multiplied by 2 to obtain 24.\n- 24 is not found in nums. Thus, 24 is returned.\n
\n\n

Example 2:

\n\n
\nInput: nums = [2,7,9], original = 4\nOutput: 4\nExplanation:\n- 4 is not found in nums. Thus, 4 is returned.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "将找到的值乘以 2", "translatedContent": "

给你一个整数数组 nums ，另给你一个整数 original ，这是需要在 nums 中搜索的第一个数字。

\n\n

接下来，你需要按下述步骤操作：

\n\n
    \n\t
  1. 如果在 nums 中找到 original ，将 original 乘以 2 ，得到新 original（即，令 original = 2 * original）。
    2. \n\t
  2. 否则，停止这一过程。
    3. \n\t
  3. 只要能在数组中找到新 original ，就对新 original 继续 重复 这一过程。
    4. \n
\n\n

返回 original 的 最终 值。

\n\n

 

\n\n

示例 1：

\n\n
\n输入：nums = [5,3,6,1,12], original = 3\n输出：24\n解释： \n- 3 能在 nums 中找到。3 * 2 = 6 。\n- 6 能在 nums 中找到。6 * 2 = 12 。\n- 12 能在 nums 中找到。12 * 2 = 24 。\n- 24 不能在 nums 中找到。因此，返回 24 。\n
\n\n

示例 2：

\n\n
\n输入：nums = [2,7,9], original = 4\n输出：4\n解释：\n- 4 不能在 nums 中找到。因此，返回 4 。\n
\n\n

 

\n\n

提示：

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