{ "data": { "question": { "questionId": "1000313", "questionFrontendId": "剑指 Offer II 053", "categoryTitle": "LCOF2", "boundTopicId": 910307, "title": "二叉搜索树中的中序后继", "titleSlug": "P5rCT8", "content": "

English description is not available for the problem. Please switch to Chinese.

\n", "translatedTitle": "二叉搜索树中的中序后继", "translatedContent": "

给定一棵二叉搜索树和其中的一个节点 p ,找到该节点在树中的中序后继。如果节点没有中序后继,请返回 null

\n\n

节点 p 的后继是值比 p.val 大的节点中键值最小的节点,即按中序遍历的顺序节点 p 的下一个节点。

\n\n

 

\n\n

示例 1:

\n\n

\"\"

\n\n
\n输入:root = [2,1,3], p = 1\n输出:2\n解释:这里 1 的中序后继是 2。请注意 p 和返回值都应是 TreeNode 类型。\n
\n\n

示例 2:

\n\n

\"\"

\n\n
\n输入:root = [5,3,6,2,4,null,null,1], p = 6\n输出:null\n解释:因为给出的节点没有中序后继,所以答案就返回 null 了。\n
\n\n

 

\n\n

提示:

\n\n\n\n

 

\n\n

注意:本题与主站 285 题相同: https://leetcode-cn.com/problems/inorder-successor-in-bst/

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{\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc inorderSuccessor(root *TreeNode, p *TreeNode) *TreeNode {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var _value: Int) {\n * var value: Int = _value\n * var left: TreeNode = null\n * var right: TreeNode = null\n * }\n */\n\nobject Solution {\n def inorderSuccessor(root: TreeNode, p: TreeNode): TreeNode = {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int = 0) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\n\nclass Solution {\n fun inorderSuccessor(root: TreeNode?, p: TreeNode?): TreeNode? {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option>>,\n// pub right: Option>>,\n// }\n// \n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn inorder_successor(root: Option>>, p: Option>>) -> Option>> {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($value) { $this->val = $value; }\n * }\n */\n\nclass Solution {\n /**\n * @param TreeNode $root\n * @param TreeNode $p\n * @return TreeNode\n */\n function inorderSuccessor($root, $p) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction inorderSuccessor(root: TreeNode | null, p: TreeNode | null): TreeNode | null {\n\t\n};", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"11.3K\", \"totalSubmission\": \"17.8K\", \"totalAcceptedRaw\": 11272, \"totalSubmissionRaw\": 17815, \"acRate\": \"63.3%\"}", "hints": [], "solution": null, "status": null, "sampleTestCase": "[2,1,3]\n1", "metaData": "{\"name\": \"inorderSuccessor\", \"params\": [{\"name\": \"root\", \"type\": \"TreeNode\"}, {\"name\": \"p\", \"type\": \"integer\"}], \"return\": {\"type\": \"TreeNode\"}}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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