You are given two strings s and t of the same length, and two integer arrays nextCost and previousCost.
In one operation, you can pick any index i of s, and perform either one of the following actions:
s[i] to the next letter in the alphabet. If s[i] == 'z', you should replace it with 'a'. This operation costs nextCost[j] where j is the index of s[i] in the alphabet.s[i] to the previous letter in the alphabet. If s[i] == 'a', you should replace it with 'z'. This operation costs previousCost[j] where j is the index of s[i] in the alphabet.The shift distance is the minimum total cost of operations required to transform s into t.
Return the shift distance from s to t.
\n
Example 1:
\n\nInput: s = "abab", t = "baba", nextCost = [100,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0], previousCost = [1,100,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
\n\nOutput: 2
\n\nExplanation:
\n\ni = 0 and shift s[0] 25 times to the previous character for a total cost of 1.i = 1 and shift s[1] 25 times to the next character for a total cost of 0.i = 2 and shift s[2] 25 times to the previous character for a total cost of 1.i = 3 and shift s[3] 25 times to the next character for a total cost of 0.Example 2:
\n\nInput: s = "leet", t = "code", nextCost = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1], previousCost = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1]
\n\nOutput: 31
\n\nExplanation:
\n\ni = 0 and shift s[0] 9 times to the previous character for a total cost of 9.i = 1 and shift s[1] 10 times to the next character for a total cost of 10.i = 2 and shift s[2] 1 time to the previous character for a total cost of 1.i = 3 and shift s[3] 11 times to the next character for a total cost of 11.\n
Constraints:
\n\n1 <= s.length == t.length <= 105s and t consist only of lowercase English letters.nextCost.length == previousCost.length == 260 <= nextCost[i], previousCost[i] <= 109(a, b), the cost of turning a into b is equal to the minimum between: \r\ni < j, nextCost[i] + nextCost[i + 1] + … + nextCost[j - 1], and nextCost[i] + nextCost[i + 1] + … + nextCost[25] + nextCost[0] + … + nextCost[j - 1] otherwise.i < j, prevCost[i] + prevCost[i - 1] + … + prevCost[0] + prevCost[25] + … + prevCost[j + 1], and prevCost[i] + prevCost[i - 1] + … + prevCost[j + 1] otherwise.i and j are the indices of a and b in the alphabet.",
"The shift distance is the sum of costs of turning s[i] into t[i]."
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