You are given a string target, an array of strings words, and an integer array costs, both arrays of the same length.
Imagine an empty string s.
You can perform the following operation any number of times (including zero):
\n\ni in the range [0, words.length - 1].words[i] to s.costs[i].Return the minimum cost to make s equal to target. If it's not possible, return -1.
\n
Example 1:
\n\nInput: target = "abcdef", words = ["abdef","abc","d","def","ef"], costs = [100,1,1,10,5]
\n\nOutput: 7
\n\nExplanation:
\n\nThe minimum cost can be achieved by performing the following operations:
\n\n"abc" to s at a cost of 1, resulting in s = "abc"."d" to s at a cost of 1, resulting in s = "abcd"."ef" to s at a cost of 5, resulting in s = "abcdef".Example 2:
\n\nInput: target = "aaaa", words = ["z","zz","zzz"], costs = [1,10,100]
\n\nOutput: -1
\n\nExplanation:
\n\nIt is impossible to make s equal to target, so we return -1.
\n
Constraints:
\n\n1 <= target.length <= 5 * 1041 <= words.length == costs.length <= 5 * 1041 <= words[i].length <= target.lengthwords[i].length is less than or equal to 5 * 104.target and words[i] consist only of lowercase English letters.1 <= costs[i] <= 104Compiled with clang 17 using the latest C++ 23 standard, and libstdc++ provided by GCC 13.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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