Alice and Bob want to water n plants in their garden. The plants are arranged in a row and are labeled from 0 to n - 1 from left to right where the ith plant is located at x = i.
Each plant needs a specific amount of water. Alice and Bob have a watering can each, initially full. They water the plants in the following way:
\n\n0th plant. Bob waters the plants in order from right to left, starting from the (n - 1)th plant. They begin watering the plants simultaneously.Given a 0-indexed integer array plants of n integers, where plants[i] is the amount of water the ith plant needs, and two integers capacityA and capacityB representing the capacities of Alice's and Bob's watering cans respectively, return the number of times they have to refill to water all the plants.
\n
Example 1:
\n\n\nInput: plants = [2,2,3,3], capacityA = 5, capacityB = 5\nOutput: 1\nExplanation:\n- Initially, Alice and Bob have 5 units of water each in their watering cans.\n- Alice waters plant 0, Bob waters plant 3.\n- Alice and Bob now have 3 units and 2 units of water respectively.\n- Alice has enough water for plant 1, so she waters it. Bob does not have enough water for plant 2, so he refills his can then waters it.\nSo, the total number of times they have to refill to water all the plants is 0 + 0 + 1 + 0 = 1.\n\n\n
Example 2:
\n\n\nInput: plants = [2,2,3,3], capacityA = 3, capacityB = 4\nOutput: 2\nExplanation:\n- Initially, Alice and Bob have 3 units and 4 units of water in their watering cans respectively.\n- Alice waters plant 0, Bob waters plant 3.\n- Alice and Bob now have 1 unit of water each, and need to water plants 1 and 2 respectively.\n- Since neither of them have enough water for their current plants, they refill their cans and then water the plants.\nSo, the total number of times they have to refill to water all the plants is 0 + 1 + 1 + 0 = 2.\n\n\n
Example 3:
\n\n\nInput: plants = [5], capacityA = 10, capacityB = 8\nOutput: 0\nExplanation:\n- There is only one plant.\n- Alice's watering can has 10 units of water, whereas Bob's can has 8 units. Since Alice has more water in her can, she waters this plant.\nSo, the total number of times they have to refill is 0.\n\n\n
\n
Constraints:
\n\nn == plants.length1 <= n <= 1051 <= plants[i] <= 106max(plants[i]) <= capacityA, capacityB <= 109Alice 和 Bob 打算给花园里的 n 株植物浇水。植物排成一行，从左到右进行标记，编号从 0 到 n - 1 。其中，第 i 株植物的位置是 x = i 。
每一株植物都需要浇特定量的水。Alice 和 Bob 每人有一个水罐，最初是满的 。他们按下面描述的方式完成浇水：
\n\n0 开始。Bob 按 从右到左 的顺序给植物浇水，从植物 n - 1 开始。他们 同时 给植物浇水。给你一个下标从 0 开始的整数数组 plants ，数组由 n 个整数组成。其中，plants[i] 为第 i 株植物需要的水量。另有两个整数 capacityA 和 capacityB 分别表示 Alice 和 Bob 水罐的容量。返回两人浇灌所有植物过程中重新灌满水罐的 次数 。
\n\n
示例 1：
\n\n\n输入：plants = [2,2,3,3], capacityA = 5, capacityB = 5\n输出：1\n解释：\n- 最初，Alice 和 Bob 的水罐中各有 5 单元水。\n- Alice 给植物 0 浇水，Bob 给植物 3 浇水。\n- Alice 和 Bob 现在分别剩下 3 单元和 2 单元水。\n- Alice 有足够的水给植物 1 ，所以她直接浇水。Bob 的水不够给植物 2 ，所以他先重新装满水，再浇水。\n所以，两人浇灌所有植物过程中重新灌满水罐的次数 = 0 + 0 + 1 + 0 = 1 。\n\n
示例 2：
\n\n\n输入：plants = [2,2,3,3], capacityA = 3, capacityB = 4\n输出：2\n解释：\n- 最初，Alice 的水罐中有 3 单元水，Bob 的水罐中有 4 单元水。\n- Alice 给植物 0 浇水，Bob 给植物 3 浇水。\n- Alice 和 Bob 现在都只有 1 单元水，并分别需要给植物 1 和植物 2 浇水。\n- 由于他们的水量均不足以浇水，所以他们重新灌满水罐再进行浇水。\n所以，两人浇灌所有植物过程中重新灌满水罐的次数 = 0 + 1 + 1 + 0 = 2 。\n\n
示例 3：
\n\n\n输入：plants = [5], capacityA = 10, capacityB = 8\n输出：0\n解释：\n- 只有一株植物\n- Alice 的水罐有 10 单元水，Bob 的水罐有 8 单元水。因此 Alice 的水罐中水更多，她会给这株植物浇水。\n所以，两人浇灌所有植物过程中重新灌满水罐的次数 = 0 。\n\n
\n\n
提示：
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