{ "data": { "question": { "questionId": "100", "questionFrontendId": "100", "categoryTitle": "Algorithms", "boundTopicId": 1369, "title": "Same Tree", "titleSlug": "same-tree", "content": "
Given the roots of two binary trees p
and q
, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
\n\n\n
Example 1:
\n\n\nInput: p = [1,2,3], q = [1,2,3]\nOutput: true\n\n\n
Example 2:
\n\n\nInput: p = [1,2], q = [1,null,2]\nOutput: false\n\n\n
Example 3:
\n\n\nInput: p = [1,2,1], q = [1,1,2]\nOutput: false\n\n\n
\n
Constraints:
\n\n[0, 100]
.-104 <= Node.val <= 104
给你两棵二叉树的根节点 p
和 q
,编写一个函数来检验这两棵树是否相同。
如果两个树在结构上相同,并且节点具有相同的值,则认为它们是相同的。
\n\n\n\n
示例 1:
\n\n\n输入:p = [1,2,3], q = [1,2,3]\n输出:true\n\n\n
示例 2:
\n\n\n输入:p = [1,2], q = [1,null,2]\n输出:false\n\n\n
示例 3:
\n\n\n输入:p = [1,2,1], q = [1,1,2]\n输出:false\n\n\n
\n\n
提示:
\n\n[0, 100]
内-104 <= Node.val <= 104
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\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
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