You are given an even integer n. You initially have a permutation perm of size n where perm[i] == i (0-indexed).
In one operation, you will create a new array arr, and for each i:
i % 2 == 0, then arr[i] = perm[i / 2].i % 2 == 1, then arr[i] = perm[n / 2 + (i - 1) / 2].You will then assign arr to perm.
Return the minimum non-zero number of operations you need to perform on perm to return the permutation to its initial value.
\n
Example 1:
\n\n\nInput: n = 2\nOutput: 1\nExplanation: perm = [0,1] initially.\nAfter the 1st operation, perm = [0,1]\nSo it takes only 1 operation.\n\n\n
Example 2:
\n\n\nInput: n = 4\nOutput: 2\nExplanation: perm = [0,1,2,3] initially.\nAfter the 1st operation, perm = [0,2,1,3]\nAfter the 2nd operation, perm = [0,1,2,3]\nSo it takes only 2 operations.\n\n\n
Example 3:
\n\n\nInput: n = 6\nOutput: 4\n\n\n
\n
Constraints:
\n\n2 <= n <= 1000n is even.给你一个偶数 n ，已知存在一个长度为 n 的排列 perm ，其中 perm[i] == i（下标 从 0 开始 计数）。
一步操作中，你将创建一个新数组 arr ，对于每个 i ：
i % 2 == 0 ，那么 arr[i] = perm[i / 2]i % 2 == 1 ，那么 arr[i] = perm[n / 2 + (i - 1) / 2]然后将 arr 赋值给 perm 。
要想使 perm 回到排列初始值，至少需要执行多少步操作？返回最小的 非零 操作步数。
\n\n
示例 1：
\n\n\n输入：n = 2\n输出：1\n解释：最初，perm = [0,1]\n第 1 步操作后，perm = [0,1]\n所以，仅需执行 1 步操作\n\n
示例 2：
\n\n\n输入：n = 4\n输出：2\n解释：最初，perm = [0,1,2,3]\n第 1 步操作后，perm = [0,2,1,3]\n第 2 步操作后，perm = [0,1,2,3]\n所以，仅需执行 2 步操作\n\n
示例 3：
\n\n\n输入：n = 6\n输出：4\n\n\n
\n\n
提示：
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