{ "data": { "question": { "questionId": "100092", "questionFrontendId": "LCP 02", "categoryTitle": "Algorithms", "boundTopicId": 23271, "title": "Deep Dark Fraction", "titleSlug": "deep-dark-fraction", "content": "

English description is not available for the problem. Please switch to Chinese.
\r\n 

\r\n", "translatedTitle": "分式化简", "translatedContent": "

有一个同学在学习分式。他需要将一个连分数化成最简分数，你能帮助他吗？

\n\n

\"\"

\n\n

连分数是形如上图的分式。在本题中，所有系数都是大于等于0的整数。

\n\n

 

\n\n

输入的cont代表连分数的系数（cont[0]代表上图的a0，以此类推）。返回一个长度为2的数组[n, m]，使得连分数的值等于n / m，且n, m最大公约数为1。

\n\n

 

\n\n

示例 1：

\n\n
\n输入：cont = [3, 2, 0, 2]\n输出：[13, 4]\n解释：原连分数等价于3 + (1 / (2 + (1 / (0 + 1 / 2))))。注意[26, 8], [-13, -4]都不是正确答案。
\n\n

示例 2：

\n\n
\n输入：cont = [0, 0, 3]\n输出：[3, 1]\n解释：如果答案是整数，令分母为1即可。
\n\n

 

\n\n

限制：

\n\n
    \n\t
  1. cont[i] >= 0
    2. \n\t
  2. 1 <= cont的长度 <= 10
    3. \n\t
  3. cont最后一个元素不等于0
    4. \n\t
  4. 答案的n, m的取值都能被32位int整型存下（即不超过2 ^ 31 - 1）。
    5. \n
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