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You are given three integers start, finish, and limit. You are also given a 0-indexed string s representing a positive integer.
A positive integer x is called powerful if it ends with s (in other words, s is a suffix of x) and each digit in x is at most limit.
Return the total number of powerful integers in the range [start..finish].
A string x is a suffix of a string y if and only if x is a substring of y that starts from some index (including 0) in y and extends to the index y.length - 1. For example, 25 is a suffix of 5125 whereas 512 is not.
\n
Example 1:
\n\n\nInput: start = 1, finish = 6000, limit = 4, s = "124"\nOutput: 5\nExplanation: The powerful integers in the range [1..6000] are 124, 1124, 2124, 3124, and, 4124. All these integers have each digit <= 4, and "124" as a suffix. Note that 5124 is not a powerful integer because the first digit is 5 which is greater than 4.\nIt can be shown that there are only 5 powerful integers in this range.\n\n\n
Example 2:
\n\n\nInput: start = 15, finish = 215, limit = 6, s = "10"\nOutput: 2\nExplanation: The powerful integers in the range [15..215] are 110 and 210. All these integers have each digit <= 6, and "10" as a suffix.\nIt can be shown that there are only 2 powerful integers in this range.\n\n\n
Example 3:
\n\n\nInput: start = 1000, finish = 2000, limit = 4, s = "3000"\nOutput: 0\nExplanation: All integers in the range [1000..2000] are smaller than 3000, hence "3000" cannot be a suffix of any integer in this range.\n\n\n
\n
Constraints:
\n\n1 <= start <= finish <= 10151 <= limit <= 91 <= s.length <= floor(log10(finish)) + 1s only consists of numeric digits which are at most limit.s does not have leading zeros.[1, x].",
                "Let dp[i][j] be the number of integers that have i digits (with allowed leading 0s) and j refers to the comparison between the current number and the prefix of x, j == 0 if the i-digit number formed currently is identical to the leftmost i digits of x, else if j ==1 it means the i-digit number is smaller than the leftmost i digits of x.",
                "The answer is count[finish] - count[start - 1], where count[i] refers to the number of powerful integers in the range [1..i]."
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