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            "categoryTitle": "Algorithms",
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            "title": "Sum of Number and Its Reverse",
            "titleSlug": "sum-of-number-and-its-reverse",
            "content": "<p>Given a <strong>non-negative</strong> integer <code>num</code>, return <code>true</code><em> if </em><code>num</code><em> can be expressed as the sum of any <strong>non-negative</strong> integer and its reverse, or </em><code>false</code><em> otherwise.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 443\n<strong>Output:</strong> true\n<strong>Explanation:</strong> 172 + 271 = 443 so we return true.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 63\n<strong>Output:</strong> false\n<strong>Explanation:</strong> 63 cannot be expressed as the sum of a non-negative integer and its reverse so we return false.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 181\n<strong>Output:</strong> true\n<strong>Explanation:</strong> 140 + 041 = 181 so we return true. Note that when a number is reversed, there may be leading zeros.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= num &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "反转之后的数字和",
            "translatedContent": "<p>给你一个 <strong>非负</strong> 整数 <code>num</code> 。如果存在某个 <strong>非负</strong> 整数 <code>k</code> 满足 <code>k + reverse(k) = num</code>&nbsp; ，则返回 <code>true</code> ；否则，返回<em> </em><code>false</code> 。</p>\n\n<p><code>reverse(k)</code> 表示 <code>k</code> 反转每个数位后得到的数字。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 443\n<strong>输出：</strong>true\n<strong>解释：</strong>172 + 271 = 443 ，所以返回 true 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 63\n<strong>输出：</strong>false\n<strong>解释：</strong>63 不能表示为非负整数及其反转后数字之和，返回 false 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>num = 181\n<strong>输出：</strong>true\n<strong>解释：</strong>140 + 041 = 181 ，所以返回 true 。注意，反转后的数字可能包含前导零。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= num &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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