Given a 0-indexed string word and a character ch, reverse the segment of word that starts at index 0 and ends at the index of the first occurrence of ch (inclusive). If the character ch does not exist in word, do nothing.
word = "abcdefd" and ch = "d", then you should reverse the segment that starts at 0 and ends at 3 (inclusive). The resulting string will be "dcbaefd".Return the resulting string.
\n\n\n
Example 1:
\n\n\nInput: word = "abcdefd", ch = "d"\nOutput: "dcbaefd"\nExplanation: The first occurrence of "d" is at index 3. \nReverse the part of word from 0 to 3 (inclusive), the resulting string is "dcbaefd".\n\n\n
Example 2:
\n\n\nInput: word = "xyxzxe", ch = "z"\nOutput: "zxyxxe"\nExplanation: The first and only occurrence of "z" is at index 3.\nReverse the part of word from 0 to 3 (inclusive), the resulting string is "zxyxxe".\n\n\n
Example 3:
\n\n\nInput: word = "abcd", ch = "z"\nOutput: "abcd"\nExplanation: "z" does not exist in word.\nYou should not do any reverse operation, the resulting string is "abcd".\n\n\n
\n
Constraints:
\n\n1 <= word.length <= 250word consists of lowercase English letters.ch is a lowercase English letter.给你一个下标从 0 开始的字符串 word 和一个字符 ch 。找出 ch 第一次出现的下标 i ，反转 word 中从下标 0 开始、直到下标 i 结束（含下标 i ）的那段字符。如果 word 中不存在字符 ch ，则无需进行任何操作。
word = \"abcdefd\" 且 ch = \"d\" ，那么你应该 反转 从下标 0 开始、直到下标 3 结束（含下标 3 ）。结果字符串将会是 \"dcbaefd\" 。返回 结果字符串 。
\n\n\n\n
示例 1：
\n\n输入：word = \"abcdefd\", ch = \"d\"\n输出：\"dcbaefd\"\n解释：\"d\" 第一次出现在下标 3 。 \n反转从下标 0 到下标 3（含下标 3）的这段字符，结果字符串是 \"dcbaefd\" 。\n\n\n
示例 2：
\n\n输入：word = \"xyxzxe\", ch = \"z\"\n输出：\"zxyxxe\"\n解释：\"z\" 第一次也是唯一一次出现是在下标 3 。\n反转从下标 0 到下标 3（含下标 3）的这段字符，结果字符串是 \"zxyxxe\" 。\n\n\n
示例 3：
\n\n输入：word = \"abcd\", ch = \"z\"\n输出：\"abcd\"\n解释：\"z\" 不存在于 word 中。\n无需执行反转操作，结果字符串是 \"abcd\" 。\n\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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