{ "data": { "question": { "questionId": "3250", "questionFrontendId": "2975", "categoryTitle": "Algorithms", "boundTopicId": 2575705, "title": "Maximum Square Area by Removing Fences From a Field", "titleSlug": "maximum-square-area-by-removing-fences-from-a-field", "content": "

There is a large (m - 1) x (n - 1) rectangular field with corners at (1, 1) and (m, n) containing some horizontal and vertical fences given in arrays hFences and vFences respectively.

\n\n

Horizontal fences are from the coordinates (hFences[i], 1) to (hFences[i], n) and vertical fences are from the coordinates (1, vFences[i]) to (m, vFences[i]).

\n\n

Return the maximum area of a square field that can be formed by removing some fences (possibly none) or -1 if it is impossible to make a square field.

\n\n

Since the answer may be large, return it modulo 109 + 7.

\n\n

Note: The field is surrounded by two horizontal fences from the coordinates (1, 1) to (1, n) and (m, 1) to (m, n) and two vertical fences from the coordinates (1, 1) to (m, 1) and (1, n) to (m, n). These fences cannot be removed.

\n\n

 

\n

Example 1:

\n\n

\"\"

\n\n
\nInput: m = 4, n = 3, hFences = [2,3], vFences = [2]\nOutput: 4\nExplanation: Removing the horizontal fence at 2 and the vertical fence at 2 will give a square field of area 4.\n
\n\n

Example 2:

\n\n

\"\"

\n\n
\nInput: m = 6, n = 7, hFences = [2], vFences = [4]\nOutput: -1\nExplanation: It can be proved that there is no way to create a square field by removing fences.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "移除栅栏得到的正方形田地的最大面积", "translatedContent": "

有一个大型的 (m - 1) x (n - 1) 矩形田地，其两个对角分别是 (1, 1) 和 (m, n) ，田地内部有一些水平栅栏和垂直栅栏，分别由数组 hFences 和 vFences 给出。

\n\n

水平栅栏为坐标 (hFences[i], 1) 到 (hFences[i], n)，垂直栅栏为坐标 (1, vFences[i]) 到 (m, vFences[i]) 。

\n\n

返回通过 移除 一些栅栏（可能不移除）所能形成的最大面积的 正方形 田地的面积，或者如果无法形成正方形田地则返回 -1。

\n\n

由于答案可能很大，所以请返回结果对 109 + 7 取余 后的值。

\n\n

注意：田地外围两个水平栅栏（坐标 (1, 1) 到 (1, n) 和坐标 (m, 1) 到 (m, n) ）以及两个垂直栅栏（坐标 (1, 1) 到 (m, 1) 和坐标 (1, n) 到 (m, n) ）所包围。这些栅栏 不能 被移除。

\n\n

 

\n\n

示例 1：

\n\n

\"\"

\n\n
\n输入：m = 4, n = 3, hFences = [2,3], vFences = [2]\n输出：4\n解释：移除位于 2 的水平栅栏和位于 2 的垂直栅栏将得到一个面积为 4 的正方形田地。\n
\n\n

示例 2：

\n\n

\"\"

\n\n
\n输入：m = 6, n = 7, hFences = [2], vFences = [4]\n输出：-1\n解释：可以证明无法通过移除栅栏形成正方形田地。\n
\n\n

 

\n\n

提示：

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(listof exact-integer?) (listof exact-integer?) exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec maximize_square_area(M :: integer(), N :: integer(), HFences :: [integer()], VFences :: [integer()]) -> integer().\nmaximize_square_area(M, N, HFences, VFences) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec maximize_square_area(m :: integer, n :: integer, h_fences :: [integer], v_fences :: [integer]) :: integer\n def maximize_square_area(m, n, h_fences, v_fences) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"3.8K\", \"totalSubmission\": \"14K\", \"totalAcceptedRaw\": 3809, \"totalSubmissionRaw\": 14045, \"acRate\": \"27.1%\"}", "hints": [ "Put 1 and m into hFences. The differences of any two values in the new hFences can be a horizontal edge of a rectangle.", "Similarly put 1 and n into vFences. The differences of any two values in the new vFences can be a vertical edge of a rectangle.", "Our goal is to find the maximum common value in both parts." ], "solution": null, "status": null, "sampleTestCase": "4\n3\n[2,3]\n[2]", "metaData": "{\n \"name\": \"maximizeSquareArea\",\n \"params\": [\n {\n \"name\": \"m\",\n \"type\": \"integer\"\n },\n {\n \"type\": \"integer\",\n \"name\": \"n\"\n },\n {\n \"type\": \"integer[]\",\n \"name\": \"hFences\"\n },\n {\n \"type\": \"integer[]\",\n \"name\": \"vFences\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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