You have n bags numbered from 0 to n - 1. You are given two 0-indexed integer arrays capacity and rocks. The ith bag can hold a maximum of capacity[i] rocks and currently contains rocks[i] rocks. You are also given an integer additionalRocks, the number of additional rocks you can place in any of the bags.
Return the maximum number of bags that could have full capacity after placing the additional rocks in some bags.
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Example 1:
\n\n\nInput: capacity = [2,3,4,5], rocks = [1,2,4,4], additionalRocks = 2\nOutput: 3\nExplanation:\nPlace 1 rock in bag 0 and 1 rock in bag 1.\nThe number of rocks in each bag are now [2,3,4,4].\nBags 0, 1, and 2 have full capacity.\nThere are 3 bags at full capacity, so we return 3.\nIt can be shown that it is not possible to have more than 3 bags at full capacity.\nNote that there may be other ways of placing the rocks that result in an answer of 3.\n\n\n
Example 2:
\n\n\nInput: capacity = [10,2,2], rocks = [2,2,0], additionalRocks = 100\nOutput: 3\nExplanation:\nPlace 8 rocks in bag 0 and 2 rocks in bag 2.\nThe number of rocks in each bag are now [10,2,2].\nBags 0, 1, and 2 have full capacity.\nThere are 3 bags at full capacity, so we return 3.\nIt can be shown that it is not possible to have more than 3 bags at full capacity.\nNote that we did not use all of the additional rocks.\n\n\n
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Constraints:
\n\nn == capacity.length == rocks.length1 <= n <= 5 * 1041 <= capacity[i] <= 1090 <= rocks[i] <= capacity[i]1 <= additionalRocks <= 109现有编号从 0 到 n - 1 的 n 个背包。给你两个下标从 0 开始的整数数组 capacity 和 rocks 。第 i 个背包最大可以装 capacity[i] 块石头，当前已经装了 rocks[i] 块石头。另给你一个整数 additionalRocks ，表示你可以放置的额外石头数量，石头可以往 任意 背包中放置。
请你将额外的石头放入一些背包中，并返回放置后装满石头的背包的 最大 数量。
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示例 1：
\n\n\n输入：capacity = [2,3,4,5], rocks = [1,2,4,4], additionalRocks = 2\n输出：3\n解释：\n1 块石头放入背包 0 ，1 块石头放入背包 1 。\n每个背包中的石头总数是 [2,3,4,4] 。\n背包 0 、背包 1 和 背包 2 都装满石头。\n总计 3 个背包装满石头，所以返回 3 。\n可以证明不存在超过 3 个背包装满石头的情况。\n注意，可能存在其他放置石头的方案同样能够得到 3 这个结果。\n\n\n
示例 2：
\n\n\n输入：capacity = [10,2,2], rocks = [2,2,0], additionalRocks = 100\n输出：3\n解释：\n8 块石头放入背包 0 ，2 块石头放入背包 2 。\n每个背包中的石头总数是 [10,2,2] 。\n背包 0 、背包 1 和背包 2 都装满石头。\n总计 3 个背包装满石头，所以返回 3 。\n可以证明不存在超过 3 个背包装满石头的情况。\n注意，不必用完所有的额外石头。\n\n\n
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提示：
\n\nn == capacity.length == rocks.length1 <= n <= 5 * 1041 <= capacity[i] <= 1090 <= rocks[i] <= capacity[i]1 <= additionalRocks <= 109\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, 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