You are given an m x n matrix mat that has its rows sorted in non-decreasing order and an integer k.
You are allowed to choose exactly one element from each row to form an array.
\n\nReturn the kth smallest array sum among all possible arrays.
\n
Example 1:
\n\n\nInput: mat = [[1,3,11],[2,4,6]], k = 5\nOutput: 7\nExplanation: Choosing one element from each row, the first k smallest sum are:\n[1,2], [1,4], [3,2], [3,4], [1,6]. Where the 5th sum is 7.\n\n\n
Example 2:
\n\n\nInput: mat = [[1,3,11],[2,4,6]], k = 9\nOutput: 17\n\n\n
Example 3:
\n\n\nInput: mat = [[1,10,10],[1,4,5],[2,3,6]], k = 7\nOutput: 9\nExplanation: Choosing one element from each row, the first k smallest sum are:\n[1,1,2], [1,1,3], [1,4,2], [1,4,3], [1,1,6], [1,5,2], [1,5,3]. Where the 7th sum is 9. \n\n\n
\n
Constraints:
\n\nm == mat.lengthn == mat.length[i]1 <= m, n <= 401 <= mat[i][j] <= 50001 <= k <= min(200, nm)mat[i] is a non-decreasing array.给你一个 m * n 的矩阵 mat，以及一个整数 k ，矩阵中的每一行都以非递减的顺序排列。
你可以从每一行中选出 1 个元素形成一个数组。返回所有可能数组中的第 k 个 最小 数组和。
\n\n\n\n
示例 1：
\n\n输入：mat = [[1,3,11],[2,4,6]], k = 5\n输出：7\n解释：从每一行中选出一个元素，前 k 个和最小的数组分别是：\n[1,2], [1,4], [3,2], [3,4], [1,6]。其中第 5 个的和是 7 。\n\n
示例 2：
\n\n输入：mat = [[1,3,11],[2,4,6]], k = 9\n输出：17\n\n\n
示例 3：
\n\n输入：mat = [[1,10,10],[1,4,5],[2,3,6]], k = 7\n输出：9\n解释：从每一行中选出一个元素，前 k 个和最小的数组分别是：\n[1,1,2], [1,1,3], [1,4,2], [1,4,3], [1,1,6], [1,5,2], [1,5,3]。其中第 7 个的和是 9 。 \n\n\n
示例 4：
\n\n输入：mat = [[1,1,10],[2,2,9]], k = 7\n输出：12\n\n\n
\n\n
提示：
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