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            "categoryTitle": "Algorithms",
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            "title": "Find Duplicate File in System",
            "titleSlug": "find-duplicate-file-in-system",
            "content": "<p>Given a list <code>paths</code> of directory info, including the directory path, and all the files with contents in this directory, return <em>all the duplicate files in the file system in terms of their paths</em>. You may return the answer in <strong>any order</strong>.</p>\n\n<p>A group of duplicate files consists of at least two files that have the same content.</p>\n\n<p>A single directory info string in the input list has the following format:</p>\n\n<ul>\n\t<li><code>&quot;root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)&quot;</code></li>\n</ul>\n\n<p>It means there are <code>n</code> files <code>(f1.txt, f2.txt ... fn.txt)</code> with content <code>(f1_content, f2_content ... fn_content)</code> respectively in the directory &quot;<code>root/d1/d2/.../dm&quot;</code>. Note that <code>n &gt;= 1</code> and <code>m &gt;= 0</code>. If <code>m = 0</code>, it means the directory is just the root directory.</p>\n\n<p>The output is a list of groups of duplicate file paths. For each group, it contains all the file paths of the files that have the same content. A file path is a string that has the following format:</p>\n\n<ul>\n\t<li><code>&quot;directory_path/file_name.txt&quot;</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<pre><strong>Input:</strong> paths = [\"root/a 1.txt(abcd) 2.txt(efgh)\",\"root/c 3.txt(abcd)\",\"root/c/d 4.txt(efgh)\",\"root 4.txt(efgh)\"]\n<strong>Output:</strong> [[\"root/a/2.txt\",\"root/c/d/4.txt\",\"root/4.txt\"],[\"root/a/1.txt\",\"root/c/3.txt\"]]\n</pre><p><strong class=\"example\">Example 2:</strong></p>\n<pre><strong>Input:</strong> paths = [\"root/a 1.txt(abcd) 2.txt(efgh)\",\"root/c 3.txt(abcd)\",\"root/c/d 4.txt(efgh)\"]\n<strong>Output:</strong> [[\"root/a/2.txt\",\"root/c/d/4.txt\"],[\"root/a/1.txt\",\"root/c/3.txt\"]]\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= paths.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= paths[i].length &lt;= 3000</code></li>\n\t<li><code>1 &lt;= sum(paths[i].length) &lt;= 5 * 10<sup>5</sup></code></li>\n\t<li><code>paths[i]</code> consist of English letters, digits, <code>&#39;/&#39;</code>, <code>&#39;.&#39;</code>, <code>&#39;(&#39;</code>, <code>&#39;)&#39;</code>, and <code>&#39; &#39;</code>.</li>\n\t<li>You may assume no files or directories share the same name in the same directory.</li>\n\t<li>You may assume each given directory info represents a unique directory. A single blank space separates the directory path and file info.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong></p>\n\n<ul>\n\t<li>Imagine you are given a real file system, how will you search files? DFS or BFS?</li>\n\t<li>If the file content is very large (GB level), how will you modify your solution?</li>\n\t<li>If you can only read the file by 1kb each time, how will you modify your solution?</li>\n\t<li>What is the time complexity of your modified solution? What is the most time-consuming part and memory-consuming part of it? How to optimize?</li>\n\t<li>How to make sure the duplicated files you find are not false positive?</li>\n</ul>\n",
            "translatedTitle": "在系统中查找重复文件",
            "translatedContent": "<p>给你一个目录信息列表&nbsp;<code>paths</code> ，包括目录路径，以及该目录中的所有文件及其内容，请你按路径返回文件系统中的所有重复文件。答案可按 <strong>任意顺序</strong> 返回。</p>\n\n<p>一组重复的文件至少包括 <strong>两个 </strong>具有完全相同内容的文件。</p>\n\n<p><strong>输入 </strong>列表中的单个目录信息字符串的格式如下：</p>\n\n<ul>\n\t<li><code>\"root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)\"</code></li>\n</ul>\n\n<p>这意味着，在目录&nbsp;<code>root/d1/d2/.../dm</code>&nbsp;下，有 <code>n</code> 个文件 ( <code>f1.txt</code>,&nbsp;<code>f2.txt</code>&nbsp;...&nbsp;<code>fn.txt</code> ) 的内容分别是 ( <code>f1_content</code>,&nbsp;<code>f2_content</code>&nbsp;...&nbsp;<code>fn_content</code> ) 。注意：<code>n &gt;= 1</code> 且 <code>m &gt;= 0</code> 。如果 <code>m = 0</code> ，则表示该目录是根目录。</p>\n\n<p><strong>输出 </strong>是由 <strong>重复文件路径组</strong> 构成的列表。其中每个组由所有具有相同内容文件的文件路径组成。文件路径是具有下列格式的字符串：</p>\n\n<ul>\n\t<li><code>\"directory_path/file_name.txt\"</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>paths = [\"root/a 1.txt(abcd) 2.txt(efgh)\",\"root/c 3.txt(abcd)\",\"root/c/d 4.txt(efgh)\",\"root 4.txt(efgh)\"]\n<strong>输出：</strong>[[\"root/a/2.txt\",\"root/c/d/4.txt\",\"root/4.txt\"],[\"root/a/1.txt\",\"root/c/3.txt\"]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>paths = [\"root/a 1.txt(abcd) 2.txt(efgh)\",\"root/c 3.txt(abcd)\",\"root/c/d 4.txt(efgh)\"]\n<strong>输出：</strong>[[\"root/a/2.txt\",\"root/c/d/4.txt\"],[\"root/a/1.txt\",\"root/c/3.txt\"]]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= paths.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= paths[i].length &lt;= 3000</code></li>\n\t<li><code>1 &lt;= sum(paths[i].length) &lt;= 5 * 10<sup>5</sup></code></li>\n\t<li><code>paths[i]</code> 由英文字母、数字、字符 <code>'/'</code>、<code>'.'</code>、<code>'('</code>、<code>')'</code> 和 <code>' '</code> 组成</li>\n\t<li>你可以假设在同一目录中没有任何文件或目录共享相同的名称。</li>\n\t<li>你可以假设每个给定的目录信息代表一个唯一的目录。目录路径和文件信息用单个空格分隔。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong></p>\n\n<ul>\n\t<li>假设您有一个真正的文件系统，您将如何搜索文件？广度搜索还是宽度搜索？</li>\n\t<li>如果文件内容非常大（GB级别），您将如何修改您的解决方案？</li>\n\t<li>如果每次只能读取 1 kb 的文件，您将如何修改解决方案？</li>\n\t<li>修改后的解决方案的时间复杂度是多少？其中最耗时的部分和消耗内存的部分是什么？如何优化？</li>\n\t<li>如何确保您发现的重复文件不是误报？</li>\n</ul>\n",
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