{ "data": { "question": { "questionId": "833", "questionFrontendId": "815", "categoryTitle": "Algorithms", "boundTopicId": 1306, "title": "Bus Routes", "titleSlug": "bus-routes", "content": "
You are given an array routes
representing bus routes where routes[i]
is a bus route that the ith
bus repeats forever.
routes[0] = [1, 5, 7]
, this means that the 0th
bus travels in the sequence 1 -> 5 -> 7 -> 1 -> 5 -> 7 -> 1 -> ...
forever.You will start at the bus stop source
(You are not on any bus initially), and you want to go to the bus stop target
. You can travel between bus stops by buses only.
Return the least number of buses you must take to travel from source
to target
. Return -1
if it is not possible.
\n
Example 1:
\n\n\nInput: routes = [[1,2,7],[3,6,7]], source = 1, target = 6\nOutput: 2\nExplanation: The best strategy is take the first bus to the bus stop 7, then take the second bus to the bus stop 6.\n\n\n
Example 2:
\n\n\nInput: routes = [[7,12],[4,5,15],[6],[15,19],[9,12,13]], source = 15, target = 12\nOutput: -1\n\n\n
\n\n
\n
Constraints:
\n\n1 <= routes.length <= 500
.1 <= routes[i].length <= 105
routes[i]
are unique.sum(routes[i].length) <= 105
0 <= routes[i][j] < 106
0 <= source, target < 106
给你一个数组 routes
,表示一系列公交线路,其中每个 routes[i]
表示一条公交线路,第 i
辆公交车将会在上面循环行驶。
routes[0] = [1, 5, 7]
表示第 0
辆公交车会一直按序列 1 -> 5 -> 7 -> 1 -> 5 -> 7 -> 1 -> ...
这样的车站路线行驶。现在从 source
车站出发(初始时不在公交车上),要前往 target
车站。 期间仅可乘坐公交车。
求出 最少乘坐的公交车数量 。如果不可能到达终点车站,返回 -1
。
\n\n
示例 1:
\n\n\n输入:routes = [[1,2,7],[3,6,7]], source = 1, target = 6\n输出:2\n解释:最优策略是先乘坐第一辆公交车到达车站 7 , 然后换乘第二辆公交车到车站 6 。 \n\n\n
示例 2:
\n\n\n输入:routes = [[7,12],[4,5,15],[6],[15,19],[9,12,13]], source = 15, target = 12\n输出:-1\n\n\n
\n\n
提示:
\n\n1 <= routes.length <= 500
.1 <= routes[i].length <= 105
routes[i]
中的所有值 互不相同sum(routes[i].length) <= 105
0 <= routes[i][j] < 106
0 <= source, target < 106
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