{ "data": { "question": { "questionId": "2707", "questionFrontendId": "2570", "categoryTitle": "Algorithms", "boundTopicId": 2115709, "title": "Merge Two 2D Arrays by Summing Values", "titleSlug": "merge-two-2d-arrays-by-summing-values", "content": "

You are given two 2D integer arrays nums1 and nums2.

\n\n\n\n

Each array contains unique ids and is sorted in ascending order by id.

\n\n

Merge the two arrays into one array that is sorted in ascending order by id, respecting the following conditions:

\n\n\n\n

Return the resulting array. The returned array must be sorted in ascending order by id.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums1 = [[1,2],[2,3],[4,5]], nums2 = [[1,4],[3,2],[4,1]]\nOutput: [[1,6],[2,3],[3,2],[4,6]]\nExplanation: The resulting array contains the following:\n- id = 1, the value of this id is 2 + 4 = 6.\n- id = 2, the value of this id is 3.\n- id = 3, the value of this id is 2.\n- id = 4, the value of this id is 5 + 1 = 6.\n
\n\n

Example 2:

\n\n
\nInput: nums1 = [[2,4],[3,6],[5,5]], nums2 = [[1,3],[4,3]]\nOutput: [[1,3],[2,4],[3,6],[4,3],[5,5]]\nExplanation: There are no common ids, so we just include each id with its value in the resulting list.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "合并两个二维数组 - 求和法", "translatedContent": "

给你两个 二维 整数数组 nums1nums2.

\n\n\n\n

每个数组都包含 互不相同 的 id ,并按 id 以 递增 顺序排列。

\n\n

请你将两个数组合并为一个按 id 以递增顺序排列的数组,并符合下述条件:

\n\n\n\n

返回结果数组。返回的数组需要按 id 以递增顺序排列。

\n\n

 

\n\n

示例 1:

\n\n
输入:nums1 = [[1,2],[2,3],[4,5]], nums2 = [[1,4],[3,2],[4,1]]\n输出:[[1,6],[2,3],[3,2],[4,6]]\n解释:结果数组中包含以下元素:\n- id = 1 ,对应的值等于 2 + 4 = 6 。\n- id = 2 ,对应的值等于 3 。\n- id = 3 ,对应的值等于 2 。\n- id = 4 ,对应的值等于5 + 1 = 6 。\n
\n\n

示例 2:

\n\n
输入:nums1 = [[2,4],[3,6],[5,5]], nums2 = [[1,3],[4,3]]\n输出:[[1,3],[2,4],[3,6],[4,3],[5,5]]\n解释:不存在共同 id ,在结果数组中只需要包含每个 id 和其对应的值。\n
\n\n

 

\n\n

提示:

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