{ "data": { "question": { "questionId": "2903", "questionFrontendId": "2807", "categoryTitle": "Algorithms", "boundTopicId": 2372234, "title": "Insert Greatest Common Divisors in Linked List", "titleSlug": "insert-greatest-common-divisors-in-linked-list", "content": "
Given the head of a linked list head
, in which each node contains an integer value.
Between every pair of adjacent nodes, insert a new node with a value equal to the greatest common divisor of them.
\n\nReturn the linked list after insertion.
\n\nThe greatest common divisor of two numbers is the largest positive integer that evenly divides both numbers.
\n\n\n
Example 1:
\n\n\nInput: head = [18,6,10,3]\nOutput: [18,6,6,2,10,1,3]\nExplanation: The 1st diagram denotes the initial linked list and the 2nd diagram denotes the linked list after inserting the new nodes (nodes in blue are the inserted nodes).\n- We insert the greatest common divisor of 18 and 6 = 6 between the 1st and the 2nd nodes.\n- We insert the greatest common divisor of 6 and 10 = 2 between the 2nd and the 3rd nodes.\n- We insert the greatest common divisor of 10 and 3 = 1 between the 3rd and the 4th nodes.\nThere are no more adjacent nodes, so we return the linked list.\n\n\n
Example 2:
\n\n\nInput: head = [7]\nOutput: [7]\nExplanation: The 1st diagram denotes the initial linked list and the 2nd diagram denotes the linked list after inserting the new nodes.\nThere are no pairs of adjacent nodes, so we return the initial linked list.\n\n\n
\n
Constraints:
\n\n[1, 5000]
.1 <= Node.val <= 1000
给你一个链表的头 head
,每个结点包含一个整数值。
在相邻结点之间,请你插入一个新的结点,结点值为这两个相邻结点值的 最大公约数 。
\n\n请你返回插入之后的链表。
\n\n两个数的 最大公约数 是可以被两个数字整除的最大正整数。
\n\n\n\n
示例 1:
\n\n\n\n输入:head = [18,6,10,3]\n输出:[18,6,6,2,10,1,3]\n解释:第一幅图是一开始的链表,第二幅图是插入新结点后的图(蓝色结点为新插入结点)。\n- 18 和 6 的最大公约数为 6 ,插入第一和第二个结点之间。\n- 6 和 10 的最大公约数为 2 ,插入第二和第三个结点之间。\n- 10 和 3 的最大公约数为 1 ,插入第三和第四个结点之间。\n所有相邻结点之间都插入完毕,返回链表。\n\n\n
示例 2:
\n\n\n\n输入:head = [7]\n输出:[7]\n解释:第一幅图是一开始的链表,第二幅图是插入新结点后的图(蓝色结点为新插入结点)。\n没有相邻结点,所以返回初始链表。\n\n\n
\n\n
提示:
\n\n[1, 5000]
之间。1 <= Node.val <= 1000
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