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        "question": {
            "questionId": "623",
            "questionFrontendId": "623",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1789,
            "title": "Add One Row to Tree",
            "titleSlug": "add-one-row-to-tree",
            "content": "<p>Given the <code>root</code> of a binary tree and two integers <code>val</code> and <code>depth</code>, add a row of nodes with value <code>val</code> at the given depth <code>depth</code>.</p>\n\n<p>Note that the <code>root</code> node is at depth <code>1</code>.</p>\n\n<p>The adding rule is:</p>\n\n<ul>\n\t<li>Given the integer <code>depth</code>, for each not null tree node <code>cur</code> at the depth <code>depth - 1</code>, create two tree nodes with value <code>val</code> as <code>cur</code>&#39;s left subtree root and right subtree root.</li>\n\t<li><code>cur</code>&#39;s original left subtree should be the left subtree of the new left subtree root.</li>\n\t<li><code>cur</code>&#39;s original right subtree should be the right subtree of the new right subtree root.</li>\n\t<li>If <code>depth == 1</code> that means there is no depth <code>depth - 1</code> at all, then create a tree node with value <code>val</code> as the new root of the whole original tree, and the original tree is the new root&#39;s left subtree.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/15/addrow-tree.jpg\" style=\"width: 500px; height: 231px;\" />\n<pre>\n<strong>Input:</strong> root = [4,2,6,3,1,5], val = 1, depth = 2\n<strong>Output:</strong> [4,1,1,2,null,null,6,3,1,5]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/11/add2-tree.jpg\" style=\"width: 500px; height: 277px;\" />\n<pre>\n<strong>Input:</strong> root = [4,2,null,3,1], val = 1, depth = 3\n<strong>Output:</strong> [4,2,null,1,1,3,null,null,1]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li>The depth of the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-100 &lt;= Node.val &lt;= 100</code></li>\n\t<li><code>-10<sup>5</sup> &lt;= val &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= depth &lt;= the depth of tree + 1</code></li>\n</ul>\n",
            "translatedTitle": "在二叉树中增加一行",
            "translatedContent": "<p>给定一个二叉树的根&nbsp;<code>root</code>&nbsp;和两个整数 <code>val</code> 和&nbsp;<code>depth</code>&nbsp;，在给定的深度&nbsp;<code>depth</code>&nbsp;处添加一个值为 <code>val</code> 的节点行。</p>\n\n<p>注意，根节点&nbsp;<code>root</code>&nbsp;位于深度&nbsp;<code>1</code>&nbsp;。</p>\n\n<p>加法规则如下:</p>\n\n<ul>\n\t<li>给定整数&nbsp;<code>depth</code>，对于深度为&nbsp;<code>depth - 1</code> 的每个非空树节点 <code>cur</code> ，创建两个值为 <code>val</code> 的树节点作为 <code>cur</code> 的左子树根和右子树根。</li>\n\t<li><code>cur</code> 原来的左子树应该是新的左子树根的左子树。</li>\n\t<li><code>cur</code> 原来的右子树应该是新的右子树根的右子树。</li>\n\t<li>如果 <code>depth == 1 </code>意味着&nbsp;<code>depth - 1</code>&nbsp;根本没有深度，那么创建一个树节点，值 <code>val </code>作为整个原始树的新根，而原始树就是新根的左子树。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/03/15/addrow-tree.jpg\" style=\"height: 231px; width: 500px;\" /></p>\n\n<pre>\n<strong>输入:</strong> root = [4,2,6,3,1,5], val = 1, depth = 2\n<strong>输出:</strong> [4,1,1,2,null,null,6,3,1,5]</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/03/11/add2-tree.jpg\" style=\"height: 277px; width: 500px;\" /></p>\n\n<pre>\n<strong>输入:</strong> root = [4,2,null,3,1], val = 1, depth = 3\n<strong>输出:</strong>  [4,2,null,1,1,3,null,null,1]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>节点数在&nbsp;<code>[1, 10<sup>4</sup>]</code>&nbsp;范围内</li>\n\t<li>树的深度在&nbsp;<code>[1, 10<sup>4</sup>]</code>范围内</li>\n\t<li><code>-100 &lt;= Node.val &lt;= 100</code></li>\n\t<li><code>-10<sup>5</sup>&nbsp;&lt;= val &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= depth &lt;= the depth of tree + 1</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n    TreeNode* addOneRow(TreeNode* root, int val, int depth) {\n\n    }\n};",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     int val;\n *     TreeNode left;\n *     TreeNode right;\n *     TreeNode() {}\n *     TreeNode(int val) { this.val = val; }\n *     TreeNode(int val, TreeNode left, TreeNode right) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\nclass Solution {\n    public TreeNode addOneRow(TreeNode root, int val, int depth) {\n\n    }\n}",
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                    "lang": "Python",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode(object):\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass Solution(object):\n    def addOneRow(self, root, val, depth):\n        \"\"\"\n        :type root: TreeNode\n        :type val: int\n        :type depth: int\n        :rtype: TreeNode\n        \"\"\"",
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                    "lang": "Python3",
                    "langSlug": "python3",
                    "code": "# Definition for a binary tree node.\n# class TreeNode:\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass Solution:\n    def addOneRow(self, root: TreeNode, val: int, depth: int) -> TreeNode:",
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                    "lang": "C",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     struct TreeNode *left;\n *     struct TreeNode *right;\n * };\n */\n\n\nstruct TreeNode* addOneRow(struct TreeNode* root, int val, int depth){\n\n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public int val;\n *     public TreeNode left;\n *     public TreeNode right;\n *     public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\npublic class Solution {\n    public TreeNode AddOneRow(TreeNode root, int val, int depth) {\n\n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.left = (left===undefined ? null : left)\n *     this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} val\n * @param {number} depth\n * @return {TreeNode}\n */\nvar addOneRow = function(root, val, depth) {\n\n};",
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                    "lang": "Ruby",
                    "langSlug": "ruby",
                    "code": "# Definition for a binary tree node.\n# class TreeNode\n#     attr_accessor :val, :left, :right\n#     def initialize(val = 0, left = nil, right = nil)\n#         @val = val\n#         @left = left\n#         @right = right\n#     end\n# end\n# @param {TreeNode} root\n# @param {Integer} val\n# @param {Integer} depth\n# @return {TreeNode}\ndef add_one_row(root, val, depth)\n\nend",
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                    "lang": "Swift",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public var val: Int\n *     public var left: TreeNode?\n *     public var right: TreeNode?\n *     public init() { self.val = 0; self.left = nil; self.right = nil; }\n *     public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n *     public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n *         self.val = val\n *         self.left = left\n *         self.right = right\n *     }\n * }\n */\nclass Solution {\n    func addOneRow(_ root: TreeNode?, _ val: Int, _ depth: Int) -> TreeNode? {\n\n    }\n}",
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                {
                    "lang": "Go",
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                    "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n *     Val int\n *     Left *TreeNode\n *     Right *TreeNode\n * }\n */\nfunc addOneRow(root *TreeNode, val int, depth int) *TreeNode {\n\n}",
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                    "lang": "Kotlin",
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                    "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n *     var left: TreeNode? = null\n *     var right: TreeNode? = null\n * }\n */\nclass Solution {\n    fun addOneRow(root: TreeNode?, `val`: Int, depth: Int): TreeNode? {\n\n    }\n}",
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                    "lang": "Rust",
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                    "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n//   pub val: i32,\n//   pub left: Option<Rc<RefCell<TreeNode>>>,\n//   pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n//   #[inline]\n//   pub fn new(val: i32) -> Self {\n//     TreeNode {\n//       val,\n//       left: None,\n//       right: None\n//     }\n//   }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n    pub fn add_one_row(root: Option<Rc<RefCell<TreeNode>>>, val: i32, depth: i32) -> Option<Rc<RefCell<TreeNode>>> {\n\n    }\n}",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nfunction addOneRow(root: TreeNode | null, val: number, depth: number): TreeNode | null {\n\n};",
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                    "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%%                     left = null  :: 'null' | #tree_node{},\n%%                     right = null :: 'null' | #tree_node{}}).\n\n-spec add_one_row(Root :: #tree_node{} | null, Val :: integer(), Depth :: integer()) -> #tree_node{} | null.\nadd_one_row(Root, Val, Depth) ->\n  .",
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