Design a number container system that can do the following:
Implement the NumberContainers class:
NumberContainers() Initializes the number container system.void change(int index, int number) Fills the container at index with the number. If there is already a number at that index, replace it.int find(int number) Returns the smallest index for the given number, or -1 if there is no index that is filled by number in the system.
Example 1:
Input ["NumberContainers", "find", "change", "change", "change", "change", "find", "change", "find"] [[], [10], [2, 10], [1, 10], [3, 10], [5, 10], [10], [1, 20], [10]] Output [null, -1, null, null, null, null, 1, null, 2] Explanation NumberContainers nc = new NumberContainers(); nc.find(10); // There is no index that is filled with number 10. Therefore, we return -1. nc.change(2, 10); // Your container at index 2 will be filled with number 10. nc.change(1, 10); // Your container at index 1 will be filled with number 10. nc.change(3, 10); // Your container at index 3 will be filled with number 10. nc.change(5, 10); // Your container at index 5 will be filled with number 10. nc.find(10); // Number 10 is at the indices 1, 2, 3, and 5. Since the smallest index that is filled with 10 is 1, we return 1. nc.change(1, 20); // Your container at index 1 will be filled with number 20. Note that index 1 was filled with 10 and then replaced with 20. nc.find(10); // Number 10 is at the indices 2, 3, and 5. The smallest index that is filled with 10 is 2. Therefore, we return 2.
Constraints:
1 <= index, number <= 109105 calls will be made in total to change and find.