{ "data": { "question": { "questionId": "2417", "questionFrontendId": "2332", "boundTopicId": null, "title": "The Latest Time to Catch a Bus", "titleSlug": "the-latest-time-to-catch-a-bus", "content": "
You are given a 0-indexed integer array buses
of length n
, where buses[i]
represents the departure time of the ith
bus. You are also given a 0-indexed integer array passengers
of length m
, where passengers[j]
represents the arrival time of the jth
passenger. All bus departure times are unique. All passenger arrival times are unique.
You are given an integer capacity
, which represents the maximum number of passengers that can get on each bus.
The passengers will get on the next available bus. You can get on a bus that will depart at x
minutes if you arrive at y
minutes where y <= x
, and the bus is not full. Passengers with the earliest arrival times get on the bus first.
Return the latest time you may arrive at the bus station to catch a bus. You cannot arrive at the same time as another passenger.
\n\nNote: The arrays buses
and passengers
are not necessarily sorted.
\n
Example 1:
\n\n\nInput: buses = [10,20], passengers = [2,17,18,19], capacity = 2\nOutput: 16\nExplanation: \nThe 1st bus departs with the 1st passenger. \nThe 2nd bus departs with you and the 2nd passenger.\nNote that you must not arrive at the same time as the passengers, which is why you must arrive before the 2nd passenger to catch the bus.\n\n
Example 2:
\n\n\nInput: buses = [20,30,10], passengers = [19,13,26,4,25,11,21], capacity = 2\nOutput: 20\nExplanation: \nThe 1st bus departs with the 4th passenger. \nThe 2nd bus departs with the 6th and 2nd passengers.\nThe 3rd bus departs with the 1st passenger and you.\n\n\n
\n
Constraints:
\n\nn == buses.length
m == passengers.length
1 <= n, m, capacity <= 105
2 <= buses[i], passengers[i] <= 109
buses
is unique.passengers
is unique.Compiled with clang 11
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Most standard library headers are already included automatically for your convenience.
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