{ "data": { "question": { "questionId": "2195", "questionFrontendId": "2073", "categoryTitle": "Algorithms", "boundTopicId": 1097162, "title": "Time Needed to Buy Tickets", "titleSlug": "time-needed-to-buy-tickets", "content": "

There are n people in a line queuing to buy tickets, where the 0th person is at the front of the line and the (n - 1)th person is at the back of the line.

\n\n

You are given a 0-indexed integer array tickets of length n where the number of tickets that the ith person would like to buy is tickets[i].

\n\n

Each person takes exactly 1 second to buy a ticket. A person can only buy 1 ticket at a time and has to go back to the end of the line (which happens instantaneously) in order to buy more tickets. If a person does not have any tickets left to buy, the person will leave the line.

\n\n

Return the time taken for the person at position k (0-indexed) to finish buying tickets.

\n\n

 

\n

Example 1:

\n\n
\nInput: tickets = [2,3,2], k = 2\nOutput: 6\nExplanation: \n- In the first pass, everyone in the line buys a ticket and the line becomes [1, 2, 1].\n- In the second pass, everyone in the line buys a ticket and the line becomes [0, 1, 0].\nThe person at position 2 has successfully bought 2 tickets and it took 3 + 3 = 6 seconds.\n
\n\n

Example 2:

\n\n
\nInput: tickets = [5,1,1,1], k = 0\nOutput: 8\nExplanation:\n- In the first pass, everyone in the line buys a ticket and the line becomes [4, 0, 0, 0].\n- In the next 4 passes, only the person in position 0 is buying tickets.\nThe person at position 0 has successfully bought 5 tickets and it took 4 + 1 + 1 + 1 + 1 = 8 seconds.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "买票需要的时间", "translatedContent": "

有 n 个人前来排队买票，其中第 0 人站在队伍 最前方 ，第 (n - 1) 人站在队伍 最后方 。

\n\n

给你一个下标从 0 开始的整数数组 tickets ，数组长度为 n ，其中第 i 人想要购买的票数为 tickets[i] 。

\n\n

每个人买票都需要用掉 恰好 1 秒 。一个人 一次只能买一张票 ，如果需要购买更多票，他必须走到  队尾 重新排队（瞬间 发生，不计时间）。如果一个人没有剩下需要买的票，那他将会 离开 队伍。

\n\n

返回位于位置 k（下标从 0 开始）的人完成买票需要的时间（以秒为单位）。

\n\n

 

\n\n

示例 1：

\n\n
输入：tickets = [2,3,2], k = 2\n输出：6\n解释： \n- 第一轮，队伍中的每个人都买到一张票，队伍变为 [1, 2, 1] 。\n- 第二轮，队伍中的每个都又都买到一张票，队伍变为 [0, 1, 0] 。\n位置 2 的人成功买到 2 张票，用掉 3 + 3 = 6 秒。\n
\n\n

示例 2：

\n\n
输入：tickets = [5,1,1,1], k = 0\n输出：8\n解释：\n- 第一轮，队伍中的每个人都买到一张票，队伍变为 [4, 0, 0, 0] 。\n- 接下来的 4 轮，只有位置 0 的人在买票。\n位置 0 的人成功买到 5 张票，用掉 4 + 1 + 1 + 1 + 1 = 8 秒。\n
\n\n

 

\n\n

提示：

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