{ "data": { "question": { "questionId": "2470", "questionFrontendId": "2390", "categoryTitle": "Algorithms", "boundTopicId": 1774486, "title": "Removing Stars From a String", "titleSlug": "removing-stars-from-a-string", "content": "

You are given a string s, which contains stars *.

\n\n

In one operation, you can:

\n\n\n\n

Return the string after all stars have been removed.

\n\n

Note:

\n\n\n\n

 

\n

Example 1:

\n\n
\nInput: s = "leet**cod*e"\nOutput: "lecoe"\nExplanation: Performing the removals from left to right:\n- The closest character to the 1st star is 't' in "leet**cod*e". s becomes "lee*cod*e".\n- The closest character to the 2nd star is 'e' in "lee*cod*e". s becomes "lecod*e".\n- The closest character to the 3rd star is 'd' in "lecod*e". s becomes "lecoe".\nThere are no more stars, so we return "lecoe".
\n\n

Example 2:

\n\n
\nInput: s = "erase*****"\nOutput: ""\nExplanation: The entire string is removed, so we return an empty string.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "从字符串中移除星号", "translatedContent": "

给你一个包含若干星号 * 的字符串 s

\n\n

在一步操作中,你可以:

\n\n\n\n

返回移除 所有 星号之后的字符串

\n\n

注意:

\n\n\n\n

 

\n\n

示例 1:

\n\n
\n输入:s = \"leet**cod*e\"\n输出:\"lecoe\"\n解释:从左到右执行移除操作:\n- 距离第 1 个星号最近的字符是 \"leet**cod*e\" 中的 't' ,s 变为 \"lee*cod*e\" 。\n- 距离第 2 个星号最近的字符是 \"lee*cod*e\" 中的 'e' ,s 变为 \"lecod*e\" 。\n- 距离第 3 个星号最近的字符是 \"lecod*e\" 中的 'd' ,s 变为 \"lecoe\" 。\n不存在其他星号,返回 \"lecoe\" 。
\n\n

示例 2:

\n\n
\n输入:s = \"erase*****\"\n输出:\"\"\n解释:整个字符串都会被移除,所以返回空字符串。\n
\n\n

 

\n\n

提示:

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