Given an array of integers nums, you start with an initial positive value startValue.
In each iteration, you calculate the step by step sum of startValue plus elements in nums (from left to right).
Return the minimum positive value of startValue such that the step by step sum is never less than 1.
\n\n\n
Example 1:
\n\n\nInput: nums = [-3,2,-3,4,2]\nOutput: 5\nExplanation: If you choose startValue = 4, in the third iteration your step by step sum is less than 1.\nstep by step sum\nstartValue = 4 | startValue = 5 | nums\n (4 -3 ) = 1 | (5 -3 ) = 2 | -3\n (1 +2 ) = 3 | (2 +2 ) = 4 | 2\n (3 -3 ) = 0 | (4 -3 ) = 1 | -3\n (0 +4 ) = 4 | (1 +4 ) = 5 | 4\n (4 +2 ) = 6 | (5 +2 ) = 7 | 2\n\n\n
Example 2:
\n\n\nInput: nums = [1,2]\nOutput: 1\nExplanation: Minimum start value should be positive. \n\n\n
Example 3:
\n\n\nInput: nums = [1,-2,-3]\nOutput: 5\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 100-100 <= nums[i] <= 100给你一个整数数组 nums 。你可以选定任意的 正数 startValue 作为初始值。
你需要从左到右遍历 nums 数组，并将 startValue 依次累加上 nums 数组中的值。
请你在确保累加和始终大于等于 1 的前提下，选出一个最小的 正数 作为 startValue 。
\n\n\n\n
示例 1：
\n\n\n输入：nums = [-3,2,-3,4,2]\n输出：5\n解释：如果你选择 startValue = 4，在第三次累加时，和小于 1 。\n 累加求和\n startValue = 4 | startValue = 5 | nums\n (4 -3 ) = 1 | (5 -3 ) = 2 | -3\n (1 +2 ) = 3 | (2 +2 ) = 4 | 2\n (3 -3 ) = 0 | (4 -3 ) = 1 | -3\n (0 +4 ) = 4 | (1 +4 ) = 5 | 4\n (4 +2 ) = 6 | (5 +2 ) = 7 | 2\n\n\n
示例 2：
\n\n\n输入：nums = [1,2]\n输出：1\n解释：最小的 startValue 需要是正数。\n\n\n
示例 3：
\n\n\n输入：nums = [1,-2,-3]\n输出：5\n\n\n
\n\n
提示：
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