{ "data": { "question": { "questionId": "100326", "questionFrontendId": "剑指 Offer 52", "categoryTitle": "LCOF", "boundTopicId": 87896, "title": "两个链表的第一个公共节点 LCOF", "titleSlug": "liang-ge-lian-biao-de-di-yi-ge-gong-gong-jie-dian-lcof", "content": "English description is not available for the problem. Please switch to Chinese.", "translatedTitle": "两个链表的第一个公共节点", "translatedContent": "

输入两个链表，找出它们的第一个公共节点。

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如下面的两个链表：

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在节点 c1 开始相交。

\n\n

\n\n

示例 1：

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\n\n

输入：intersectVal = 8, listA = [4,1,8,4,5], listB = [5,0,1,8,4,5], skipA = 2, skipB = 3\n输出：Reference of the node with value = 8\n输入解释：相交节点的值为 8 （注意，如果两个列表相交则不能为 0）。从各自的表头开始算起，链表 A 为 [4,1,8,4,5]，链表 B 为 [5,0,1,8,4,5]。在 A 中，相交节点前有 2 个节点；在 B 中，相交节点前有 3 个节点。\n

\n\n

\n\n

示例 2：

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输入：intersectVal = 2, listA = [0,9,1,2,4], listB = [3,2,4], skipA = 3, skipB = 1\n输出：Reference of the node with value = 2\n输入解释：相交节点的值为 2 （注意，如果两个列表相交则不能为 0）。从各自的表头开始算起，链表 A 为 [0,9,1,2,4]，链表 B 为 [3,2,4]。在 A 中，相交节点前有 3 个节点；在 B 中，相交节点前有 1 个节点。\n

\n\n

\n\n

示例 3：

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输入：intersectVal = 0, listA = [2,6,4], listB = [1,5], skipA = 3, skipB = 2\n输出：null\n输入解释：从各自的表头开始算起，链表 A 为 [2,6,4]，链表 B 为 [1,5]。由于这两个链表不相交，所以 intersectVal 必须为 0，而 skipA 和 skipB 可以是任意值。\n解释：这两个链表不相交，因此返回 null。\n

\n\n

\n\n

注意：

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如果两个链表没有交点，返回 null.
在返回结果后，两个链表仍须保持原有的结构。
可假定整个链表结构中没有循环。
程序尽量满足 O(n) 时间复杂度，且仅用 O(1) 内存。
本题与主站 160 题相同：https://leetcode-cn.com/problems/intersection-of-two-linked-lists/

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