{ "data": { "question": { "questionId": "278", "questionFrontendId": "278", "categoryTitle": "Algorithms", "boundTopicId": 1507, "title": "First Bad Version", "titleSlug": "first-bad-version", "content": "
You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.
\n\nSuppose you have n
versions [1, 2, ..., n]
and you want to find out the first bad one, which causes all the following ones to be bad.
You are given an API bool isBadVersion(version)
which returns whether version
is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.
\n
Example 1:
\n\n\nInput: n = 5, bad = 4\nOutput: 4\nExplanation:\ncall isBadVersion(3) -> false\ncall isBadVersion(5) -> true\ncall isBadVersion(4) -> true\nThen 4 is the first bad version.\n\n\n
Example 2:
\n\n\nInput: n = 1, bad = 1\nOutput: 1\n\n\n
\n
Constraints:
\n\n1 <= bad <= n <= 231 - 1
你是产品经理,目前正在带领一个团队开发新的产品。不幸的是,你的产品的最新版本没有通过质量检测。由于每个版本都是基于之前的版本开发的,所以错误的版本之后的所有版本都是错的。
\n\n假设你有 n
个版本 [1, 2, ..., n]
,你想找出导致之后所有版本出错的第一个错误的版本。
你可以通过调用 bool isBadVersion(version)
接口来判断版本号 version
是否在单元测试中出错。实现一个函数来查找第一个错误的版本。你应该尽量减少对调用 API 的次数。
示例 1:
\n\n\n输入:n = 5, bad = 4\n输出:4\n解释:\n\n\n调用 isBadVersion(3) -> false \n调用 isBadVersion(5) -> true \n调用 isBadVersion(4) -> true
\n所以,4 是第一个错误的版本。
\n
示例 2:
\n\n\n输入:n = 1, bad = 1\n输出:1\n\n\n
\n\n
提示:
\n\n1 <= bad <= n <= 231 - 1
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
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