You are given an integer array nums.
You must replace exactly one element in the array with any integer value in the range [-105, 105] (inclusive).
After performing this single replacement, determine the maximum possible product of any three elements at distinct indices from the modified array.
\n\nReturn an integer denoting the maximum product achievable.
\n\n\n
Example 1:
\n\nInput: nums = [-5,7,0]
\n\nOutput: 3500000
\n\nExplanation:
\n\nReplacing 0 with -105 gives the array [-5, 7, -105], which has a product (-5) * 7 * (-105) = 3500000. The maximum product is 3500000.
Example 2:
\n\nInput: nums = [-4,-2,-1,-3]
\n\nOutput: 1200000
\n\nExplanation:
\n\nTwo ways to achieve the maximum product include:
\n\n[-4, -2, -3] → replace -2 with 105 → product = (-4) * 105 * (-3) = 1200000.[-4, -1, -3] → replace -1 with 105 → product = (-4) * 105 * (-3) = 1200000.Example 3:
\n\nInput: nums = [0,10,0]
\n\nOutput: 0
\n\nExplanation:
\n\nThere is no way to replace an element with another integer and not have a 0 in the array. Hence, the product of all three elements will always be 0, and the maximum product is 0.
\n\n
Constraints:
\n\n3 <= nums.length <= 105-105 <= nums[i] <= 105给你一个整数数组 nums。
你 必须 将数组中的 恰好一个 元素替换为范围 [-105, 105]（包含边界）内的 任意 整数。
在进行这一替换操作后，请确定从修改后的数组中选择 任意三个互不相同的下标 对应的元素所能得到的 最大乘积 。
\n\n返回一个整数，表示可以达到的 最大乘积 。
\n\n\n\n
示例 1：
\n\n输入： nums = [-5,7,0]
\n\n输出： 3500000
\n\n解释：
\n\n用 -105 替换 0，可得数组 [-5, 7, -105]，其乘积为 (-5) * 7 * (-105) = 3500000。最大乘积为 3500000。
示例 2：
\n\n输入： nums = [-4,-2,-1,-3]
\n\n输出： 1200000
\n\n解释：
\n\n有两种方法可以达到最大乘积：
\n\n[-4, -2, -3] → 将 -2 替换为 105 → 乘积为 (-4) * 105 * (-3) = 1200000。[-4, -1, -3] → 将 -1 替换为 105 → 乘积为 (-4) * 105 * (-3) = 1200000。示例 3：
\n\n输入： nums = [0,10,0]
\n\n输出： 0
\n\n解释：
\n\n无论将哪个元素替换为另一个整数，数组始终会包含 0。因此，三个元素的乘积始终为 0，最大乘积为 0。
\n\n\n
提示：
\n\n3 <= nums.length <= 105-105 <= nums[i] <= 105nums and 105."
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