You are given a positive integer num consisting of exactly four digits. Split num into two new integers new1 and new2 by using the digits found in num. Leading zeros are allowed in new1 and new2, and all the digits found in num must be used.
num = 2932, you have the following digits: two 2's, one 9 and one 3. Some of the possible pairs [new1, new2] are [22, 93], [23, 92], [223, 9] and [2, 329].Return the minimum possible sum of new1 and new2.
\n
Example 1:
\n\n\nInput: num = 2932\nOutput: 52\nExplanation: Some possible pairs [new1, new2] are [29, 23], [223, 9], etc.\nThe minimum sum can be obtained by the pair [29, 23]: 29 + 23 = 52.\n\n\n
Example 2:
\n\n\nInput: num = 4009\nOutput: 13\nExplanation: Some possible pairs [new1, new2] are [0, 49], [490, 0], etc. \nThe minimum sum can be obtained by the pair [4, 9]: 4 + 9 = 13.\n\n\n
\n
Constraints:
\n\n1000 <= num <= 9999给你一个四位 正 整数 num 。请你使用 num 中的 数位 ，将 num 拆成两个新的整数 new1 和 new2 。new1 和 new2 中可以有 前导 0 ，且 num 中 所有 数位都必须使用。
num = 2932 ，你拥有的数位包括：两个 2 ，一个 9 和一个 3 。一些可能的 [new1, new2] 数对为 [22, 93]，[23, 92]，[223, 9] 和 [2, 329] 。请你返回可以得到的 new1 和 new2 的 最小 和。
\n\n
示例 1：
\n\n输入：num = 2932\n输出：52\n解释：可行的 [new1, new2] 数对为 [29, 23] ，[223, 9] 等等。\n最小和为数对 [29, 23] 的和：29 + 23 = 52 。\n\n\n
示例 2：
\n\n输入：num = 4009\n输出：13\n解释：可行的 [new1, new2] 数对为 [0, 49] ，[490, 0] 等等。\n最小和为数对 [4, 9] 的和：4 + 9 = 13 。\n\n\n
\n\n
提示：
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