You are given an integer array nums and an integer m.
Return the maximum product of the first and last elements of any subsequence of nums of size m.
\n
Example 1:
\n\nInput: nums = [-1,-9,2,3,-2,-3,1], m = 1
\n\nOutput: 81
\n\nExplanation:
\n\nThe subsequence [-9] has the largest product of the first and last elements: -9 * -9 = 81. Therefore, the answer is 81.
Example 2:
\n\nInput: nums = [1,3,-5,5,6,-4], m = 3
\n\nOutput: 20
\n\nExplanation:
\n\nThe subsequence [-5, 6, -4] has the largest product of the first and last elements.
Example 3:
\n\nInput: nums = [2,-1,2,-6,5,2,-5,7], m = 2
\n\nOutput: 35
\n\nExplanation:
\n\nThe subsequence [5, 7] has the largest product of the first and last elements.
\n
Constraints:
\n\n1 <= nums.length <= 105-105 <= nums[i] <= 1051 <= m <= nums.length给你一个整数数组 nums 和一个整数 m。
返回任意大小为 m 的 子序列 中首尾元素乘积的最大值。
子序列 是可以通过删除原数组中的一些元素（或不删除任何元素），且不改变剩余元素顺序而得到的数组。
\n\n\n\n
示例 1：
\n\n输入： nums = [-1,-9,2,3,-2,-3,1], m = 1
\n\n输出： 81
\n\n解释：
\n\n子序列 [-9] 的首尾元素乘积最大：-9 * -9 = 81。因此，答案是 81。
示例 2：
\n\n输入： nums = [1,3,-5,5,6,-4], m = 3
\n\n输出： 20
\n\n解释：
\n\n子序列 [-5, 6, -4] 的首尾元素乘积最大。
示例 3：
\n\n输入： nums = [2,-1,2,-6,5,2,-5,7], m = 2
\n\n输出： 35
\n\n解释：
\n\n子序列 [5, 7] 的首尾元素乘积最大。
\n\n
提示:
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"exampleTestcases": "[-1,-9,2,3,-2,-3,1]\n1\n[1,3,-5,5,6,-4]\n3\n[2,-1,2,-6,5,2,-5,7]\n2",
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